CAIE M2 2012 November — Question 3 7 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2012
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (1D)
TypeAcceleration as function of velocity (separation of variables)
DifficultyStandard +0.3 This is a standard mechanics question involving Newton's second law with resistance proportional to velocity. Part (i) is straightforward force equation manipulation (2 marks). Part (ii) requires separating variables and integrating a simple linear differential equation, which is a routine M2 technique, though the integration and algebra require care.
Spec6.06a Variable force: dv/dt or v*dv/dx methods

A particle \(P\) of mass \(0.2\) kg is released from rest and falls vertically. At time \(t\) s after release \(P\) has speed \(v\) m s\(^{-1}\). A resisting force of magnitude \(0.8v\) N acts on \(P\).
  1. Show that the acceleration of \(P\) is \((10 - 4v)\) m s\(^{-2}\). [2]
  2. Find the value of \(v\) when \(t = 0.6\). [5]

(i)
AnswerMarks Guidance
\(0.2 \, dv/dt = 0.2g - 0.8v\)M1 Use Newton's Second Law, – sign essential
\(a = (dv/dt) = 10 - 4v\)AG A1 [2]
(ii)
AnswerMarks Guidance
\(\int 1/(10 - 4v) \, dv = \int dt\)M1 Separates variables and attempts to integrate
\(-\frac{1}{4} \ln(10 - 4v) = t (+c)\)A1
\([c = -\frac{1}{4} \ln 10]\)M1 Attempts to find the constant or uses the correct limits
\(-\frac{1}{4} \ln(10 - 4v) = 0.6 - \frac{1}{4} \ln4\)A1
\(v = 2.27\)A1 [5]
## (i)

$0.2 \, dv/dt = 0.2g - 0.8v$ | M1 | Use Newton's Second Law, – sign essential
$a = (dv/dt) = 10 - 4v$ | AG A1 [2] |

## (ii)

$\int 1/(10 - 4v) \, dv = \int dt$ | M1 | Separates variables and attempts to integrate
$-\frac{1}{4} \ln(10 - 4v) = t (+c)$ | A1 |
$[c = -\frac{1}{4} \ln 10]$ | M1 | Attempts to find the constant or uses the correct limits
$-\frac{1}{4} \ln(10 - 4v) = 0.6 - \frac{1}{4} \ln4$ | A1 |
$v = 2.27$ | A1 [5] |
A particle $P$ of mass $0.2$ kg is released from rest and falls vertically. At time $t$ s after release $P$ has speed $v$ m s$^{-1}$. A resisting force of magnitude $0.8v$ N acts on $P$.

\begin{enumerate}[label=(\roman*)]
\item Show that the acceleration of $P$ is $(10 - 4v)$ m s$^{-2}$. [2]
\item Find the value of $v$ when $t = 0.6$. [5]
\end{enumerate}

\hfill \mbox{\textit{CAIE M2 2012 Q3 [7]}}