CAIE M2 2011 November — Question 1 5 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2011
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeRod hinged to wall with rough contact at free end
DifficultyStandard +0.3 This is a straightforward 2D statics problem requiring moments about a point and resolution of forces. The setup is simple (rod perpendicular to wall, single string), and the methods are standard M2 techniques: take moments about A to find T, then resolve forces to find friction coefficient. Slightly easier than average due to the perpendicular orientation simplifying calculations.
Spec3.03u Static equilibrium: on rough surfaces3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force6.04e Rigid body equilibrium: coplanar forces

\includegraphics{figure_1} A non-uniform rod \(AB\), of length 0.6 m and weight 9 N, has its centre of mass 0.4 m from \(A\). The end \(A\) of the rod is in contact with a rough vertical wall. The rod is held in equilibrium, perpendicular to the wall, by means of a light string attached to \(B\). The string is inclined at \(30°\) to the horizontal. The tension in the string is \(T\) N (see diagram).
  1. Calculate \(T\). [2]
  2. Find the least possible value of the coefficient of friction at \(A\). [3]

AnswerMarks Guidance
(i) \(9 \times 0.4 = 0.6 \times T\sin30\)M1 Moments about A
\(T = 12N\)A1 [2]
(ii) \(\mu = (9 - 12\sin30)/(12\cos30)\)M1 For resolving horizontally and vertically
\(\mu = (9 - 12\sin30)/(12\cos30)\)M1 For using \(F = \mu R\)
\(\mu = 0.289\)A1 [3]
**(i)** $9 \times 0.4 = 0.6 \times T\sin30$ | M1 | Moments about A
$T = 12N$ | A1 | [2]

**(ii)** $\mu = (9 - 12\sin30)/(12\cos30)$ | M1 | For resolving horizontally and vertically
$\mu = (9 - 12\sin30)/(12\cos30)$ | M1 | For using $F = \mu R$
$\mu = 0.289$ | A1 | [3]
\includegraphics{figure_1}

A non-uniform rod $AB$, of length 0.6 m and weight 9 N, has its centre of mass 0.4 m from $A$. The end $A$ of the rod is in contact with a rough vertical wall. The rod is held in equilibrium, perpendicular to the wall, by means of a light string attached to $B$. The string is inclined at $30°$ to the horizontal. The tension in the string is $T$ N (see diagram).

\begin{enumerate}[label=(\roman*)]
\item Calculate $T$. [2]
\item Find the least possible value of the coefficient of friction at $A$. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE M2 2011 Q1 [5]}}