CAIE M2 2016 June — Question 1 4 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2016
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeTime when specific condition met
DifficultyStandard +0.3 This is a straightforward projectiles question requiring students to find when speed equals 12 m/s using the standard formula v² = u² - 2g(s_y) or component methods, then double the time to maximum speed. It's slightly above average difficulty due to requiring the speed condition rather than just range/height, but the method is standard and well-practiced in M2 courses.
Spec3.02i Projectile motion: constant acceleration model

A small ball is projected with speed \(16 \text{ ms}^{-1}\) at an angle of \(45°\) above the horizontal from a point on horizontal ground. Calculate the period of time, before the ball lands, for which the speed of the ball is less than \(12 \text{ ms}^{-1}\). [4]

Question 1:
AnswerMarks
1v2 122 (16cos45)2
= –
v = 4
–4 = 4 – gt
AnswerMarks
t = 0.8 sM1
A1
M1
AnswerMarks
A14
Question 1:
1 | v2 122 (16cos45)2
= –
v = 4
–4 = 4 – gt
t = 0.8 s | M1
A1
M1
A1 | 4
A small ball is projected with speed $16 \text{ ms}^{-1}$ at an angle of $45°$ above the horizontal from a point on horizontal ground. Calculate the period of time, before the ball lands, for which the speed of the ball is less than $12 \text{ ms}^{-1}$. [4]

\hfill \mbox{\textit{CAIE M2 2016 Q1 [4]}}