| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Session | Specimen |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Work done and energy |
| Type | Lifting objects vertically |
| Difficulty | Easy -1.2 This is a straightforward application of basic formulas: work = mgh and power = work/time. Both parts require simple substitution into standard equations with no problem-solving, making it easier than average for A-level mechanics. |
| Spec | 6.02a Work done: concept and definition6.02k Power: rate of doing work |
| Answer | Marks | Guidance |
|---|---|---|
| 1(i) | 200g × 0.7 | 1 |
| Work done = 1400 J | 1 | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| 1(ii) | 1400 / 1.2 | 1 |
| Average Power = 1170 W | 1 | A1 |
Question 1:
--- 1(i) ---
1(i) | 200g × 0.7 | 1 | M1 | For using WD = mg × h
Work done = 1400 J | 1 | A1
2
--- 1(ii) ---
1(ii) | 1400 / 1.2 | 1 | M1 | For using Power = WD / Time
Average Power = 1170 W | 1 | A1
2A weightlifter performs an exercise in which he raises a mass of 200 kg from rest vertically through a distance of 0.7 m and holds it at that height.
\begin{enumerate}[label=(\roman*)]
\item Find the work done by the weightlifter. [2]
\item Given that the time taken to raise the mass is 1.2 s, find the average power developed by the weightlifter. [2]
\end{enumerate}
\hfill \mbox{\textit{CAIE M1 Q1 [4]}}