CAIE M1 2019 November — Question 3 5 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2019
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicForces, equilibrium and resultants
TypeParticle suspended by strings
DifficultyModerate -0.3 This is a straightforward 3-force equilibrium problem requiring resolution of forces in two perpendicular directions. Students must find the geometry (3-4-5 triangle gives angles), then resolve vertically and horizontally to find two tensions. While it requires multiple steps, the techniques are standard and the geometry is simple, making it slightly easier than average.
Spec3.03b Newton's first law: equilibrium3.03m Equilibrium: sum of resolved forces = 03.03n Equilibrium in 2D: particle under forces

\includegraphics{figure_3} A particle \(P\) of mass 0.3 kg is held in equilibrium above a horizontal plane by a force of magnitude 5 N, acting vertically upwards. The particle is attached to two strings \(PA\) and \(PB\) of lengths 0.9 m and 1.2 m respectively. The points \(A\) and \(B\) lie on the plane and angle \(APB = 90°\) (see diagram). Find the tension in each of the strings. [5]

Question 3:
AnswerMarks
34 3
T × +T × +0.3g =5
AnswerMarks Guidance
A 5 B 5M1 Resolving vertically
3 4
T × =T ×
AnswerMarks Guidance
A 5 B 5M1 Resolving horizontally
A1Both correct
M1Solve for T or T
A B
T =1.6N and T = 1.2 N
AnswerMarks
A BA1
Alternative method for question 3
 5−3 T T 
= A = B
 
AnswerMarks Guidance
sin90 sin126.9 sin143.1M1 Attempt one pair of Lami’s equations
M1Attempt a second pair of Lami equations
A1Equations all correct
M1Evaluate T or T
A B
T =1.6N and T = 1.2 N
AnswerMarks Guidance
A BA1
QuestionAnswer Mark
3Alternative method for question 3
4 4
T =5cos36.9−3cos36.9=5× −3×
AnswerMarks Guidance
A 5 5M1 Resolve along PA
3 3
TB=5cos53.1−3cos53.1=5× −3×
AnswerMarks Guidance
5 5M1 Resolve along PB
A1Both correct
M1Evaluate T or T
A B
T =1.6N and T = 1.2 N
AnswerMarks
A BA1
Alternative method for question 3
Forces 2N, T and T with angles 36.9 and 53.1
AnswerMarks Guidance
A BM1 Attempt to illustrate a triangle of forces
[T =2cos36.9, T = 2cos53.1]
AnswerMarks Guidance
A BM1 Use trigonometry in the triangle to find T and T
A B
AnswerMarks
A1Both correct
M1Solve for T or T
A B
T =1.6N and T = 1.2 N
AnswerMarks
A BA1
5
AnswerMarks Guidance
QuestionAnswer Mark
Question 3:
3 | 4 3
T × +T × +0.3g =5
A 5 B 5 | M1 | Resolving vertically
3 4
T × =T ×
A 5 B 5 | M1 | Resolving horizontally
A1 | Both correct
M1 | Solve for T or T
A B
T =1.6N and T = 1.2 N
A B | A1
Alternative method for question 3
 5−3 T T 
= A = B
 
sin90 sin126.9 sin143.1 | M1 | Attempt one pair of Lami’s equations
M1 | Attempt a second pair of Lami equations
A1 | Equations all correct
M1 | Evaluate T or T
A B
T =1.6N and T = 1.2 N
A B | A1
Question | Answer | Mark | Guidance
3 | Alternative method for question 3
4 4
T =5cos36.9−3cos36.9=5× −3×
A 5 5 | M1 | Resolve along PA
3 3
TB=5cos53.1−3cos53.1=5× −3×
5 5 | M1 | Resolve along PB
A1 | Both correct
M1 | Evaluate T or T
A B
T =1.6N and T = 1.2 N
A B | A1
Alternative method for question 3
Forces 2N, T and T with angles 36.9 and 53.1
A B | M1 | Attempt to illustrate a triangle of forces
[T =2cos36.9, T = 2cos53.1]
A B | M1 | Use trigonometry in the triangle to find T and T
A B
A1 | Both correct
M1 | Solve for T or T
A B
T =1.6N and T = 1.2 N
A B | A1
5
Question | Answer | Mark | Guidance
\includegraphics{figure_3}

A particle $P$ of mass 0.3 kg is held in equilibrium above a horizontal plane by a force of magnitude 5 N, acting vertically upwards. The particle is attached to two strings $PA$ and $PB$ of lengths 0.9 m and 1.2 m respectively. The points $A$ and $B$ lie on the plane and angle $APB = 90°$ (see diagram). Find the tension in each of the strings. [5]

\hfill \mbox{\textit{CAIE M1 2019 Q3 [5]}}