CAIE M1 2019 November — Question 1 2 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2019
SessionNovember
Marks2
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeLifting objects vertically
DifficultyEasy -1.2 This is a straightforward application of the power formula P = Fv with constant velocity (so F = mg). It requires only direct substitution into a single formula with no problem-solving or multi-step reasoning, making it easier than average but not trivial since students must recognize the constant speed condition.
Spec6.02k Power: rate of doing work6.02l Power and velocity: P = Fv

A crane is lifting a load of 1250 kg vertically at a constant speed \(V\) m s\(^{-1}\). Given that the power of the crane is a constant 20 kW, find the value of \(V\). [2]

Question 1:
AnswerMarks Guidance
120000=V × 1250g M1
V=1.6A1
2
AnswerMarks Guidance
QuestionAnswer Marks
Question 1:
1 | 20000=V × 1250g | M1 | Use of P=Fv with F=mg
V=1.6 | A1
2
Question | Answer | Marks | Guidance
A crane is lifting a load of 1250 kg vertically at a constant speed $V$ m s$^{-1}$. Given that the power of the crane is a constant 20 kW, find the value of $V$. [2]

\hfill \mbox{\textit{CAIE M1 2019 Q1 [2]}}