CAIE M1 2017 November — Question 4 6 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2017
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeTime when specific condition met
DifficultyStandard +0.3 This is a straightforward two-part projectiles question requiring standard kinematic equations. Part (i) is routine (time of flight = 2u/g). Part (ii) requires finding when both particles are moving upward/downward by comparing velocities, which is a standard technique but requires careful tracking of the time offset and some algebraic manipulation. Slightly above average due to the coordination of two particles with different start times, but still a textbook exercise.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

A particle \(P\) is projected vertically upwards from horizontal ground with speed 12 m s\(^{-1}\).
  1. Find the time taken for \(P\) to return to the ground. [2]
The time in seconds after \(P\) is projected is denoted by \(t\). When \(t = 1\), a second particle \(Q\) is projected vertically upwards with speed 10 m s\(^{-1}\) from a point which is 5 m above the ground. Particles \(P\) and \(Q\) move in different vertical lines.
  1. Find the set of values of \(t\) for which the two particles are moving in the same direction. [4]

Question 4:

AnswerMarks
4(i)[12t – ½gt2 = 0]
or
AnswerMarks Guidance
[0 = 12 – gT] with t = 2T usedM1 Using s = ut + ½at2 or equivalent such as
finding time T to highest point and
doubling.
AnswerMarks
t = 2.4 sA1
2

AnswerMarks Guidance
4(ii)Critical point at t = 1.2 B1
Critical point at t = 2B1 Seen in 4(ii)
Both moving in same direction
AnswerMarks
1 < t < 1.2B1
Both moving in same direction
AnswerMarks
2 < t < 2.4B1
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 4:
--- 4(i) ---
4(i) | [12t – ½gt2 = 0]
or
[0 = 12 – gT] with t = 2T used | M1 | Using s = ut + ½at2 or equivalent such as
finding time T to highest point and
doubling.
t = 2.4 s | A1
2
--- 4(ii) ---
4(ii) | Critical point at t = 1.2 | B1 | Seen in 4(ii)
Critical point at t = 2 | B1 | Seen in 4(ii)
Both moving in same direction
1 < t < 1.2 | B1
Both moving in same direction
2 < t < 2.4 | B1
4
Question | Answer | Marks | Guidance
A particle $P$ is projected vertically upwards from horizontal ground with speed 12 m s$^{-1}$.

\begin{enumerate}[label=(\roman*)]
\item Find the time taken for $P$ to return to the ground. [2]
\end{enumerate}

The time in seconds after $P$ is projected is denoted by $t$. When $t = 1$, a second particle $Q$ is projected vertically upwards with speed 10 m s$^{-1}$ from a point which is 5 m above the ground. Particles $P$ and $Q$ move in different vertical lines.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Find the set of values of $t$ for which the two particles are moving in the same direction. [4]
\end{enumerate}

\hfill \mbox{\textit{CAIE M1 2017 Q4 [6]}}