CAIE M1 2015 June — Question 1 4 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2015
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypePower from force and speed
DifficultyEasy -1.2 This is a straightforward application of basic work and power formulas (W = Fs, P = Fv) with constant values given. Requires only direct substitution into standard formulas with no problem-solving or conceptual challenges—simpler than average A-level questions.
Spec6.02a Work done: concept and definition6.02k Power: rate of doing work

A block is pulled along a horizontal floor by a horizontal rope. The tension in the rope is 500 N and the block moves at a constant speed of \(2.75 \text{ m s}^{-1}\). Find the work done by the tension in 40 s and find the power applied by the tension. [4]

Question 1:
AnswerMarks
1[WD = 500 × 2.75 × 40]
Work done = 55000 J
55000
Power = = 1375 W
40
AnswerMarks
or Power = 500 × 2.75 = 1375 WM1
A1
M1
AnswerMarks Guidance
A14 For using WD = Fs or for using WD = Pt
For using Power = ∆WD÷∆t or for using
P = Fv
Question 1:
1 | [WD = 500 × 2.75 × 40]
Work done = 55000 J
55000
Power = = 1375 W
40
or Power = 500 × 2.75 = 1375 W | M1
A1
M1
A1 | 4 | For using WD = Fs or for using WD = Pt
For using Power = ∆WD÷∆t or for using
P = Fv
A block is pulled along a horizontal floor by a horizontal rope. The tension in the rope is 500 N and the block moves at a constant speed of $2.75 \text{ m s}^{-1}$. Find the work done by the tension in 40 s and find the power applied by the tension. [4]

\hfill \mbox{\textit{CAIE M1 2015 Q1 [4]}}