| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2014 |
| Session | June |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Friction |
| Type | Block on horizontal plane motion |
| Difficulty | Easy -1.2 This is a straightforward mechanics question requiring only direct application of F = μR and F = ma with no problem-solving insight. Part (a) is immediate recall (F_max = 0.3 × 2g), and part (b) requires one comparison and one calculation. The 5 marks reflect routine working rather than conceptual difficulty. |
| Spec | 3.03c Newton's second law: F=ma one dimension3.03r Friction: concept and vector form3.03t Coefficient of friction: F <= mu*R model |
| Answer | Marks |
|---|---|
| (ii) | 2.4 = 0.25g cosα |
| Answer | Marks |
|---|---|
| is 7/24 or 0.292 | B1 |
| Answer | Marks |
|---|---|
| A1 | [2] |
| [2] | For using |
Question 2:
--- 2 (i)
(ii) ---
2 (i)
(ii) | 2.4 = 0.25g cosα
α = 16.3
[µ = 0.28÷0.96]
Least possible value of µ
is 7/24 or 0.292 | B1
B1
M1
A1 | [2]
[2] | For using
µ = F/R or µ = tanαA block of mass $2$ kg is placed on a rough horizontal surface. The coefficient of friction between the block and the surface is $0.3$.
\begin{enumerate}[label=(\alph*)]
\item Calculate the maximum frictional force that can act on the block. [2]
\item A horizontal force of $5$ N is applied to the block. Calculate the acceleration of the block. [3]
\end{enumerate}
\hfill \mbox{\textit{CAIE M1 2014 Q2 [5]}}