CAIE M1 2009 June — Question 1 3 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2009
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicForces, equilibrium and resultants
TypeTwo particles over single pulley
DifficultyEasy -1.2 This is a straightforward equilibrium problem requiring only basic force analysis. Students need to recognize that P is in equilibrium (so tension equals its weight, 4g N) and apply vertical equilibrium to B (normal force = 5g - 4g = g N). It's simpler than average A-level questions as it involves no calculation complexity, just direct application of equilibrium conditions with clearly defined forces.
Spec3.03b Newton's first law: equilibrium3.03k Connected particles: pulleys and equilibrium

\includegraphics{figure_1} A block \(B\) of mass 5 kg is attached to one end of a light inextensible string. A particle \(P\) of mass 4 kg is attached to other end of the string. The string passes over a smooth pulley. The system is in equilibrium with the string taut and its straight parts vertical. \(B\) is at rest on the ground (see diagram). State the tension in the string and find the force exerted on \(B\) by the ground. [3]

AnswerMarks Guidance
Tension is 40 NB1 For resolving forces on B vertically
\([R + T = W]\)M1
Force exerted is 10 NA1 [3]
Tension is 40 N | B1 | For resolving forces on B vertically
$[R + T = W]$ | M1 |
Force exerted is 10 N | A1 | [3]
\includegraphics{figure_1}

A block $B$ of mass 5 kg is attached to one end of a light inextensible string. A particle $P$ of mass 4 kg is attached to other end of the string. The string passes over a smooth pulley. The system is in equilibrium with the string taut and its straight parts vertical. $B$ is at rest on the ground (see diagram). State the tension in the string and find the force exerted on $B$ by the ground. [3]

\hfill \mbox{\textit{CAIE M1 2009 Q1 [3]}}