| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2020 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Travel graphs |
| Type | Multi-stage motion with algebraic unknowns |
| Difficulty | Moderate -0.8 This is a straightforward kinematics problem using velocity-time graphs with uniform acceleration. Students need to sketch a trapezoid graph, apply the area-under-graph formula for distance, and solve simple linear equations. The problem requires only standard SUVAT concepts with no novel insight or complex problem-solving—easier than average A-level mechanics. |
| Spec | 3.02b Kinematic graphs: displacement-time and velocity-time3.02d Constant acceleration: SUVAT formulae |
| Answer | Marks | Guidance |
|---|---|---|
| 1(a) | Trapezium, deceleration steeper than acceleration | B1 |
| Time from 0 to 200 | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| 1(b) | 0.5(170+200)v=2775 | M1 |
| v=15 | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| 1(c) | a=15÷20 | M1 |
| a=0.75 | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
Question 1:
--- 1(a) ---
1(a) | Trapezium, deceleration steeper than acceleration | B1
Time from 0 to 200 | B1
2
--- 1(b) ---
1(b) | 0.5(170+200)v=2775 | M1
v=15 | A1
2
--- 1(c) ---
1(c) | a=15÷20 | M1
a=0.75 | A1
2
Question | Answer | MarksA tram starts from rest and moves with uniform acceleration for 20 s. The tram then travels at a constant speed, $V \text{ ms}^{-1}$, for 170 s before being brought to rest with a uniform deceleration of magnitude twice that of the acceleration. The total distance travelled by the tram is 2.775 km.
\begin{enumerate}[label=(\alph*)]
\item Sketch a velocity-time graph for the motion, stating the total time for which the tram is moving. [2]
\item Find $V$. [2]
\item Find the magnitude of the acceleration. [2]
\end{enumerate}
\hfill \mbox{\textit{CAIE M1 2020 Q1 [6]}}