CAIE P3 2014 June — Question 3 5 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2014
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeMixed sin and cos linear
DifficultyStandard +0.3 This requires expanding cos(x + 30°) using the compound angle formula, rearranging to form a linear equation in sin x and cos x, then solving using tan x substitution or dividing through. It's a standard compound angle equation with straightforward algebraic manipulation, slightly above average due to the multiple-step process and finding all solutions in the given interval, but still a routine P3 exercise.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

Solve the equation $$\cos(x + 30°) = 2\cos x,$$ giving all solutions in the interval \(-180° < x < 180°\). [5]

AnswerMarks
Use \(\cos(A + B)\) formula to obtain an equation in \(\cos x\) and \(\sin x\)M1
Use trig formula to obtain an equation in \(\tan x\) (or \(\cos x\) or \(\sin x\))M1
Obtain \(\tan x = \sqrt{3} - 4\), or equivalent (or find \(\cos x\) or \(\sin x\))A1
Obtain answer \(x = -66.2°\)A1
Obtain answer \(x = 113.8°\) and no others in the given intervalA1
[Ignore answers outside the given interval. Treat answers in radians as a misread \((-1.16, 1.99)\).]Total: 5 marks
[The other solution methods are via \(\cos x = \pm1/\sqrt{(1 + (\sqrt{3} - 4)^2)}\) and \(\sin x = \pm(\sqrt{3} - 4)/\sqrt{(1 + (\sqrt{3} - 4)^2)}\) .]
Use $\cos(A + B)$ formula to obtain an equation in $\cos x$ and $\sin x$ | M1 |
Use trig formula to obtain an equation in $\tan x$ (or $\cos x$ or $\sin x$) | M1 |
Obtain $\tan x = \sqrt{3} - 4$, or equivalent (or find $\cos x$ or $\sin x$) | A1 |
Obtain answer $x = -66.2°$ | A1 |
Obtain answer $x = 113.8°$ and no others in the given interval | A1 |
[Ignore answers outside the given interval. Treat answers in radians as a misread $(-1.16, 1.99)$.] | Total: 5 marks |

[The other solution methods are via $\cos x = \pm1/\sqrt{(1 + (\sqrt{3} - 4)^2)}$ and $\sin x = \pm(\sqrt{3} - 4)/\sqrt{(1 + (\sqrt{3} - 4)^2)}$ .]

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Solve the equation
$$\cos(x + 30°) = 2\cos x,$$
giving all solutions in the interval $-180° < x < 180°$. [5]

\hfill \mbox{\textit{CAIE P3 2014 Q3 [5]}}