CAIE P2 2015 June — Question 1 4 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2015
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeSolve exponential equation using logarithms
DifficultyModerate -0.8 Part (i) is a straightforward application of taking logarithms of both sides and solving for x, requiring only basic log laws. Part (ii) requires recognizing that the inequality bounds translate to -x < n < x from part (i), then counting integers in that range. While part (ii) adds a small conceptual step, the overall question remains routine with minimal problem-solving demand.
Spec1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b

  1. Use logarithms to solve the equation \(2^x = 20^5\), giving the answer correct to 3 significant figures. [2]
  2. Hence determine the number of integers \(n\) satisfying $$20^{-5} < 2^n < 20^5.$$ [2]

AnswerMarks Guidance
AnswerMarks Guidance
Introduce logarithms and use power law to obtain \(x = 21.6\)M1, A1 [2]
Obtain or imply \(-21.6\) or \(-21\) as lower value; State 43B1, B1 [2]
| Answer | Marks | Guidance |
|--------|-------|----------|
| Introduce logarithms and use power law to obtain $x = 21.6$ | M1, A1 | [2] |
| Obtain or imply $-21.6$ or $-21$ as lower value; State 43 | B1, B1 | [2] |

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\begin{enumerate}[label=(\roman*)]
\item Use logarithms to solve the equation $2^x = 20^5$, giving the answer correct to 3 significant figures. [2]

\item Hence determine the number of integers $n$ satisfying
$$20^{-5} < 2^n < 20^5.$$ [2]
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2015 Q1 [4]}}