CAIE P1 2014 November — Question 4 6 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2014
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeometric Sequences and Series
TypeRelationship between two GPs
DifficultyStandard +0.3 This question requires calculating sums to infinity using the standard formula S = a/(1-r), identifying an arithmetic progression pattern, and working backwards to find terms of a geometric sequence. While it involves multiple steps across two parts, each step uses routine A-level formulas with no novel insight required. The arithmetic progression connection is explicitly stated rather than needing to be discovered, making this slightly easier than a typical multi-part question.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04j Sum to infinity: convergent geometric series |r|<1

Three geometric progressions, \(P\), \(Q\) and \(R\), are such that their sums to infinity are the first three terms respectively of an arithmetic progression. Progression \(P\) is \(2, 1, \frac{1}{2}, \frac{1}{4}, \ldots\) Progression \(Q\) is \(3, 1, \frac{1}{3}, \frac{1}{9}, \ldots\)
  1. Find the sum to infinity of progression \(R\). [3]
  2. Given that the first term of \(R\) is 4, find the sum of the first three terms of \(R\). [3]

(i)
AnswerMarks Guidance
\(S_P = \frac{2}{1 - \frac{1}{2}}, S_P = \frac{3}{1 - \frac{1}{3}}\)M1 At least one correct
\(S_P = 4, S_Q = \frac{9}{2}\)A1 At least one correct
\(S_R = 5\) caoA1 [3]
(ii)
AnswerMarks Guidance
\(\frac{4}{1-r} = \text{their } S_R\)M1
\(r = \frac{1}{5}\)A1 [3]
\(R = 4 + \frac{4}{5} + \frac{4}{25} = 4\frac{24}{25}\) or 4.96 caoA1 [3]
### (i)
$S_P = \frac{2}{1 - \frac{1}{2}}, S_P = \frac{3}{1 - \frac{1}{3}}$ | **M1** | At least one correct
$S_P = 4, S_Q = \frac{9}{2}$ | **A1** | At least one correct
$S_R = 5$ cao | **A1** | [3]

### (ii)
$\frac{4}{1-r} = \text{their } S_R$ | **M1** | 
$r = \frac{1}{5}$ | **A1** | [3]

$R = 4 + \frac{4}{5} + \frac{4}{25} = 4\frac{24}{25}$ or 4.96 cao | **A1** | [3]

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Three geometric progressions, $P$, $Q$ and $R$, are such that their sums to infinity are the first three terms respectively of an arithmetic progression.

Progression $P$ is $2, 1, \frac{1}{2}, \frac{1}{4}, \ldots$

Progression $Q$ is $3, 1, \frac{1}{3}, \frac{1}{9}, \ldots$

\begin{enumerate}[label=(\roman*)]
\item Find the sum to infinity of progression $R$. [3]
\item Given that the first term of $R$ is 4, find the sum of the first three terms of $R$. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2014 Q4 [6]}}