CAIE P1 2014 November — Question 8 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2014
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeometric Sequences and Series
TypeFind first term from conditions
DifficultyModerate -0.3 Part (a) requires routine differentiation of the sum formula to find terms (a=31, d=-2), a standard textbook exercise. Part (b) involves setting up two equations from GP formulas (S_∞=a/(1-r)=20 and a+ar=12.8) and solving simultaneously, which requires algebraic manipulation but follows a well-practiced method. Both parts test standard techniques with no novel insight required, making this slightly easier than average.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04j Sum to infinity: convergent geometric series |r|<1

  1. The sum, \(S_n\), of the first \(n\) terms of an arithmetic progression is given by \(S_n = 32n - n^2\). Find the first term and the common difference. [3]
  2. A geometric progression in which all the terms are positive has sum to infinity 20. The sum of the first two terms is 12.8. Find the first term of the progression. [5]

(a) \(S_n = 32n - n^2\)
Set \(n\) to 1, \(a\), or \(S_1 = 31\)
Set \(n\) to 2 or other value \(S_2 = 60\)
\(\rightarrow\) 2nd term \(= 29 \rightarrow d = -2\)
(or equates formulae – compares coeffs \(n^2\), \(n\))
AnswerMarks
B1, M1, A1 [3]co; Correct method. co; [M1 only when coeffs compared]
(b) \(\frac{a}{1-r} = 20, \frac{a(1-r)^2}{1-r}\), or \(a + ar = 12.8\)
Elimination of \(\frac{a}{1-r}\) or \(a\) or \(r\)
AnswerMarks Guidance
\(\rightarrow (r = 0.6) \rightarrow a = 8\)B1, B1, M1, DM1, A1 [5] co co; 'Correct' elimination to form equation in \(a\) or \(r\); Complete method leading to \(a = \) Condone \(a = 8\) and 32
**(a)** $S_n = 32n - n^2$

Set $n$ to 1, $a$, or $S_1 = 31$

Set $n$ to 2 or other value $S_2 = 60$

$\rightarrow$ 2nd term $= 29 \rightarrow d = -2$

(or equates formulae – compares coeffs $n^2$, $n$)

| B1, M1, A1 [3] | co; Correct method. co; [M1 only when coeffs compared]

**(b)** $\frac{a}{1-r} = 20, \frac{a(1-r)^2}{1-r}$, or $a + ar = 12.8$

Elimination of $\frac{a}{1-r}$ or $a$ or $r$

$\rightarrow (r = 0.6) \rightarrow a = 8$ | B1, B1, M1, DM1, A1 [5] | co co; 'Correct' elimination to form equation in $a$ or $r$; Complete method leading to $a = $ Condone $a = 8$ and 32
\begin{enumerate}[label=(\alph*)]
\item The sum, $S_n$, of the first $n$ terms of an arithmetic progression is given by $S_n = 32n - n^2$. Find the first term and the common difference. [3]
\item A geometric progression in which all the terms are positive has sum to infinity 20. The sum of the first two terms is 12.8. Find the first term of the progression. [5]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2014 Q8 [8]}}