CAIE P1 2011 November — Question 2 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2011
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeMixed arithmetic and geometric
DifficultyEasy -1.2 This is a straightforward application of standard formulas for arithmetic and geometric series. Given the first two terms explicitly, students simply identify the common difference/ratio and substitute into memorized sum formulas (S_n = n/2(2a + (n-1)d) and S_n = a(r^n - 1)/(r-1)). No problem-solving or conceptual insight required—pure formula recall and basic arithmetic.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04i Geometric sequences: nth term and finite series sum

The first and second terms of a progression are 4 and 8 respectively. Find the sum of the first 10 terms given that the progression is
  1. an arithmetic progression, [2]
  2. a geometric progression. [2]

AnswerMarks Guidance
(i) \(\frac{5[8+9 \times 4]}{220}\)M1, A1 [2] Use correct formula with \(a=4, d=4\)
(ii) \(\frac{4(2^{10}-1)}{2-1}\)
AnswerMarks Guidance
\(4092\)M1, A1 [2] Use correct formula with \(a=4, r=2\) or \(\frac{1}{2}\); 4090 without 4092 A0
**(i)** $\frac{5[8+9 \times 4]}{220}$ | M1, A1 [2] | Use correct formula with $a=4, d=4$

**(ii)** $\frac{4(2^{10}-1)}{2-1}$ 

$4092$ | M1, A1 [2] | Use correct formula with $a=4, r=2$ or $\frac{1}{2}$; 4090 without 4092 A0

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The first and second terms of a progression are 4 and 8 respectively. Find the sum of the first 10 terms given that the progression is

\begin{enumerate}[label=(\roman*)]
\item an arithmetic progression, [2]
\item a geometric progression. [2]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2011 Q2 [4]}}