CAIE P1 2012 June — Question 8 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2012
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeTangent and sector - two tangents from external point
DifficultyModerate -0.3 This is a straightforward application of basic circle geometry, arc length, and sector area formulas. Part (i) requires simple angle calculation using tangent properties and the given constraint that A is the midpoint of OX. Parts (ii) and (iii) are direct formula applications once the angle is known. The question is slightly easier than average as it's highly structured with clear steps and uses standard techniques without requiring problem-solving insight.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

\includegraphics{figure_8} In the diagram, \(AB\) is an arc of a circle with centre \(O\) and radius \(r\). The line \(XB\) is a tangent to the circle at \(B\) and \(A\) is the mid-point of \(OX\).
  1. Show that angle \(AOB = \frac{1}{3}\pi\) radians. [2]
Express each of the following in terms of \(r\), \(\pi\) and \(\sqrt{3}\):
  1. the perimeter of the shaded region, [3]
  2. the area of the shaded region. [2]

AnswerMarks Guidance
(i) \(OBX = 90°\), \(\cos \theta = \frac{r}{2r} \to \theta = \frac{1}{3}\pi\)M1, A1 Needs \(90° +\) cos (or Pyth \(+\) sin or tan); co ag
(ii) Arc length \(AB = \frac{1}{3}r\pi\); \(BX = r\tan(\frac{1}{3}\pi) = r\sqrt{3}\); \(P = r + (\frac{1}{3}r\pi + r\sqrt{3})\)B1, B1, B1 \(r +\) sum of other two
(iii) Area \(= \frac{1}{2}r^2\sqrt{3} - \frac{1}{6}r^2\pi\)B1, B1 ✓ on \(\tan(\frac{1}{3}\pi)\); co
**(i)** $OBX = 90°$, $\cos \theta = \frac{r}{2r} \to \theta = \frac{1}{3}\pi$ | M1, A1 | Needs $90° +$ cos (or Pyth $+$ sin or tan); co ag

**(ii)** Arc length $AB = \frac{1}{3}r\pi$; $BX = r\tan(\frac{1}{3}\pi) = r\sqrt{3}$; $P = r + (\frac{1}{3}r\pi + r\sqrt{3})$ | B1, B1, B1 | $r +$ sum of other two

**(iii)** Area $= \frac{1}{2}r^2\sqrt{3} - \frac{1}{6}r^2\pi$ | B1, B1 | ✓ on $\tan(\frac{1}{3}\pi)$; co
\includegraphics{figure_8}

In the diagram, $AB$ is an arc of a circle with centre $O$ and radius $r$. The line $XB$ is a tangent to the circle at $B$ and $A$ is the mid-point of $OX$.
\begin{enumerate}[label=(\roman*)]
\item Show that angle $AOB = \frac{1}{3}\pi$ radians. [2]
\end{enumerate}

Express each of the following in terms of $r$, $\pi$ and $\sqrt{3}$:
\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item the perimeter of the shaded region, [3]

\item the area of the shaded region. [2]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2012 Q8 [7]}}