CAIE P1 2024 June — Question 4 3 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2024
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiation from First Principles
TypeComplete numerical table
DifficultyEasy -1.8 This question involves only direct substitution into a given function and calculating chord gradients using the formula (y₂-y₁)/(x₂-x₁). Part (a) requires substituting x=2.0001 into the function, part (b) is a simple gradient calculation, and part (c) asks students to observe that as the chord gets shorter, the gradient approaches the derivative—a conceptual understanding tested through pattern recognition rather than actual differentiation from first principles. Despite the topic label, no limit definition or algebraic manipulation is required; it's purely numerical and observational work suitable for early calculus students.
Spec1.07a Derivative as gradient: of tangent to curve1.07b Gradient as rate of change: dy/dx notation

The equation of a curve is \(y = \text{f}(x)\), where f\((x) = (2x - 1)\sqrt{3x - 2} - 2\). The following points lie on the curve. Non-exact values have been given correct to 5 decimal places. \(A(2, 4)\), \(B(2.0001, k)\), \(C(2.001, 4.00625)\), \(D(2.01, 4.06261)\), \(E(2.1, 4.63566)\), \(F(3, 11.22876)\)
  1. Find the value of \(k\). Give your answer correct to 5 decimal places. [1]
The table shows the gradients of the chords \(AB\), \(AC\), \(AD\) and \(AF\).
Chord\(AB\)\(AC\)\(AD\)\(AE\)\(AF\)
Gradient of chord6.25016.25116.26087.2288
  1. Find the gradient of the chord \(AE\). Give your answer correct to 4 decimal places. [1]
  2. Deduce the value of f\('(2)\) using the values in the table. [1]

Question 4:

AnswerMarks Guidance
4(a)[k] = 4.00063 B1
1

AnswerMarks Guidance
4(b)[Gradient AE] = 6.3566 B1
1

AnswerMarks Guidance
4(c)Suggests that   f'2  6.25 B1
1
AnswerMarks Guidance
QuestionAnswer Marks
Question 4:
--- 4(a) ---
4(a) | [k] = 4.00063 | B1 | CAO
1
--- 4(b) ---
4(b) | [Gradient AE] = 6.3566 | B1 | CAO
1
--- 4(c) ---
4(c) | Suggests that   f'2  6.25 | B1 | CAO
1
Question | Answer | Marks | Guidance
The equation of a curve is $y = \text{f}(x)$, where f$(x) = (2x - 1)\sqrt{3x - 2} - 2$. The following points lie on the curve. Non-exact values have been given correct to 5 decimal places.

$A(2, 4)$, $B(2.0001, k)$, $C(2.001, 4.00625)$, $D(2.01, 4.06261)$, $E(2.1, 4.63566)$, $F(3, 11.22876)$

\begin{enumerate}[label=(\alph*)]
\item Find the value of $k$. Give your answer correct to 5 decimal places. [1]
\end{enumerate}

The table shows the gradients of the chords $AB$, $AC$, $AD$ and $AF$.

\begin{center}
\begin{tabular}{|c|c|c|c|c|c|}
\hline
Chord & $AB$ & $AC$ & $AD$ & $AE$ & $AF$ \\
\hline
Gradient of chord & 6.2501 & 6.2511 & 6.2608 & & 7.2288 \\
\hline
\end{tabular}
\end{center}

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find the gradient of the chord $AE$. Give your answer correct to 4 decimal places. [1]

\item Deduce the value of f$'(2)$ using the values in the table. [1]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2024 Q4 [3]}}