Pre-U Pre-U 9794/1 2017 June — Question 11 10 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2017
SessionJune
Marks10
TopicVectors Introduction & 2D
TypeAngle between two vectors
DifficultyStandard +0.3 This is a straightforward 3D vectors question requiring standard techniques: finding position vectors of P and Q using scalar multiplication, writing parametric equations for two lines, solving simultaneously for intersection, then using the scalar product formula to find the angle between direction vectors. All steps are routine A-level procedures with no novel insight required, making it slightly easier than average.
Spec1.10g Problem solving with vectors: in geometry4.04c Scalar product: calculate and use for angles

11 The points \(A\) and \(B\) have position vectors \(2 \mathbf { i } + \mathbf { j } - 3 \mathbf { k }\) and \(3 \mathbf { i } - 2 \mathbf { j } - \mathbf { k }\) respectively, relative to the origin \(O\). The point \(P\) lies on \(O A\) extended so that \(\overrightarrow { O P } = 3 \overrightarrow { O A }\) and the point \(Q\) lies on \(O B\) extended so that \(\overrightarrow { O Q } = 2 \overrightarrow { O B }\).
  1. Find the coordinates of the point of intersection of the lines \(A Q\) and \(B P\).
  2. Find the acute angle between the lines \(A Q\) and \(B P\).

Question 11(i)
State \(\overrightarrow{OQ} = 6\mathbf{i} - 4\mathbf{j} - 2\mathbf{k}\) and \(\overrightarrow{OP} = 6\mathbf{i} + 3\mathbf{j} - 9\mathbf{k}\)
or \(AQ = 4\mathbf{i} - 5\mathbf{j} + \mathbf{k}\) and \(BP = 3\mathbf{i} + 5\mathbf{j} - 8\mathbf{k}\) B1
Form equation of line \(AQ\) and \(BP\) in form \(\mathbf{a} + \lambda\mathbf{b}\) M1
Obtain \(\mathbf{r}_{AQ} = (2\mathbf{i} + \mathbf{j} - 3\mathbf{k}) + \lambda(4\mathbf{i} - 5\mathbf{j} + \mathbf{k})\) A1
Obtain \(\mathbf{r}_{BP} = (3\mathbf{i} - 2\mathbf{j} - \mathbf{k}) + \mu(3\mathbf{i} + 5\mathbf{j} - 8\mathbf{k})\) A1
Equate line equations and solve two equations simultaneously to find some value of \(\lambda\) or \(\mu\) M1
Obtain either \(\mu = \dfrac{1}{5}\) or \(\lambda = \dfrac{2}{5}\) A1
State \(\left(\dfrac{18}{5}, -1, \dfrac{-13}{5}\right)\) Must be in coordinate form B1
Question 11(ii)
Use dot product correctly to find an angle M1
AnswerMarks Guidance
Obtain either \(\overrightarrow{AQ} = \sqrt{42}\) or \(
Obtain \(70.9°\) A1
Total: 10 marks
**Question 11(i)**
State $\overrightarrow{OQ} = 6\mathbf{i} - 4\mathbf{j} - 2\mathbf{k}$ and $\overrightarrow{OP} = 6\mathbf{i} + 3\mathbf{j} - 9\mathbf{k}$
or $AQ = 4\mathbf{i} - 5\mathbf{j} + \mathbf{k}$ and $BP = 3\mathbf{i} + 5\mathbf{j} - 8\mathbf{k}$ **B1**
Form equation of line $AQ$ and $BP$ in form $\mathbf{a} + \lambda\mathbf{b}$ **M1**
Obtain $\mathbf{r}_{AQ} = (2\mathbf{i} + \mathbf{j} - 3\mathbf{k}) + \lambda(4\mathbf{i} - 5\mathbf{j} + \mathbf{k})$ **A1**
Obtain $\mathbf{r}_{BP} = (3\mathbf{i} - 2\mathbf{j} - \mathbf{k}) + \mu(3\mathbf{i} + 5\mathbf{j} - 8\mathbf{k})$ **A1**
Equate line equations and solve two equations simultaneously to find some value of $\lambda$ or $\mu$ **M1**
Obtain either $\mu = \dfrac{1}{5}$ or $\lambda = \dfrac{2}{5}$ **A1**
State $\left(\dfrac{18}{5}, -1, \dfrac{-13}{5}\right)$ Must be in coordinate form **B1**

**Question 11(ii)**
Use dot product correctly to find an angle **M1**
Obtain either $|\overrightarrow{AQ}| = \sqrt{42}$ or $|\overrightarrow{BP}| = \sqrt{98}$ **B1**
Obtain $70.9°$ **A1**

**Total: 10 marks**
11 The points $A$ and $B$ have position vectors $2 \mathbf { i } + \mathbf { j } - 3 \mathbf { k }$ and $3 \mathbf { i } - 2 \mathbf { j } - \mathbf { k }$ respectively, relative to the origin $O$. The point $P$ lies on $O A$ extended so that $\overrightarrow { O P } = 3 \overrightarrow { O A }$ and the point $Q$ lies on $O B$ extended so that $\overrightarrow { O Q } = 2 \overrightarrow { O B }$.\\
(i) Find the coordinates of the point of intersection of the lines $A Q$ and $B P$.\\
(ii) Find the acute angle between the lines $A Q$ and $B P$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2017 Q11 [10]}}