Pre-U Pre-U 9795/2 2017 June — Question 14 9 marks

Exam BoardPre-U
ModulePre-U 9795/2 (Pre-U Further Mathematics Paper 2)
Year2017
SessionJune
Marks9
TopicHooke's law and elastic energy
TypeParticle at midpoint of string between two horizontal fixed points: horizontal surface motion
DifficultyChallenging +1.2 This is a multi-part elastic strings problem requiring Hooke's law application, SHM recognition, and energy methods. While it involves several steps and careful bookkeeping of extensions/compressions at different positions, the techniques are standard for Further Maths mechanics: setting up equations of motion, identifying SHM parameters, and using energy conservation. The geometric setup requires attention but no novel insight beyond applying familiar principles systematically.
Spec4.10f Simple harmonic motion: x'' = -omega^2 x6.02g Hooke's law: T = k*x or T = lambda*x/l6.02i Conservation of energy: mechanical energy principle

14 \includegraphics[max width=\textwidth, alt={}, center]{22640c3b-792f-4003-a4f8-78220efd73b0-5_86_1589_1297_278} A particle of mass 0.05 kg is attached to two identical light elastic strings, each of natural length 1.2 m and modulus of elasticity 0.6 N . The other ends of the strings are attached to points \(A\) and \(E\) on a smooth horizontal table. The distance \(A E\) is 2 m and points \(B , C\) and \(D\) lie between \(A\) and \(E\) so that \(A B = 0.7 \mathrm {~m} , B C = 0.1 \mathrm {~m} , C D = 0.4 \mathrm {~m}\) and \(D E = 0.8 \mathrm {~m}\) (see diagram). Initially the particle is held at \(B\) and it is then released. In the subsequent motion the displacement of the particle from \(C\), in the direction of \(A\), is denoted by \(x \mathrm {~m}\).
  1. Find the equation of motion for the particle when it is between \(B\) and \(C\).
  2. Find the velocity of the particle when it is at \(C\).
  3. Find the total time that elapses before the particle first returns to \(B\).

Part (i):
\(0.05\ddot{x} = -\dfrac{0.6}{1.2}x\) or \(\ddot{x} = -10x\) M1 Use \(ma = -\lambda x/l\). If two non-zero tensions, M0.
\(\ddot{x} = -10x\) A1 Condone \(a = -10x\)
Part (ii):
\(v = \omega\sqrt{(a^2 - x^2)} = \omega a\) M1 Use \(v = \omega\sqrt{(a^2 - x^2)}\)
\(= 0.316\) A1 \(\omega = \sqrt{10}\) and \(a = 0.1 \Rightarrow v = \sqrt{10}/10\) or awrt 0.316
Part (iii):
One complete period: \(2\pi/\omega\) M1 Use \(2\pi/\omega\) somewhere
\(= 1.987\) s A1 Correct time for SHM parts. Allow \(2\pi/\sqrt{10}\)
\(2 \times 0.4\) m at constant speed \(v\): M1 Or one way: 0.4 m at constant speed \(v\)
\(2.53\) s or \(0.8\sqrt{10}\) o.e. A1 1.26s

Total \(4.52\) A1 Allow \(\dfrac{\sqrt{10}(4+\pi)}{5}\) oe

Total: 7 marks

**Part (i):**
$0.05\ddot{x} = -\dfrac{0.6}{1.2}x$ or $\ddot{x} = -10x$ **M1** Use $ma = -\lambda x/l$. If two non-zero tensions, M0.

$\ddot{x} = -10x$ **A1** Condone $a = -10x$

**Part (ii):**
$v = \omega\sqrt{(a^2 - x^2)} = \omega a$ **M1** Use $v = \omega\sqrt{(a^2 - x^2)}$

$= 0.316$ **A1** $\omega = \sqrt{10}$ and $a = 0.1 \Rightarrow v = \sqrt{10}/10$ or awrt 0.316

**Part (iii):**
One complete period: $2\pi/\omega$ **M1** Use $2\pi/\omega$ somewhere

$= 1.987$ s **A1** Correct time for SHM parts. Allow $2\pi/\sqrt{10}$

$2 \times 0.4$ m at constant speed $v$: **M1** Or one way: 0.4 m at constant speed $v$

$2.53$ s or $0.8\sqrt{10}$ o.e. **A1** 1.26s

Total $4.52$ **A1** Allow $\dfrac{\sqrt{10}(4+\pi)}{5}$ oe

Total: **7 marks**
14\\
\includegraphics[max width=\textwidth, alt={}, center]{22640c3b-792f-4003-a4f8-78220efd73b0-5_86_1589_1297_278}

A particle of mass 0.05 kg is attached to two identical light elastic strings, each of natural length 1.2 m and modulus of elasticity 0.6 N . The other ends of the strings are attached to points $A$ and $E$ on a smooth horizontal table. The distance $A E$ is 2 m and points $B , C$ and $D$ lie between $A$ and $E$ so that $A B = 0.7 \mathrm {~m} , B C = 0.1 \mathrm {~m} , C D = 0.4 \mathrm {~m}$ and $D E = 0.8 \mathrm {~m}$ (see diagram). Initially the particle is held at $B$ and it is then released. In the subsequent motion the displacement of the particle from $C$, in the direction of $A$, is denoted by $x \mathrm {~m}$.\\
(i) Find the equation of motion for the particle when it is between $B$ and $C$.\\
(ii) Find the velocity of the particle when it is at $C$.\\
(iii) Find the total time that elapses before the particle first returns to $B$.

\hfill \mbox{\textit{Pre-U Pre-U 9795/2 2017 Q14 [9]}}