Pre-U Pre-U 9794/2 2016 Specimen — Question 2 5 marks

Exam BoardPre-U
ModulePre-U 9794/2 (Pre-U Mathematics Paper 2)
Year2016
SessionSpecimen
Marks5
TopicSine and Cosine Rules
TypeGiven area find angle/side
DifficultyModerate -0.5 This is a straightforward application of the triangle area formula (1/2)ab sin C with two sides and included angle given. Students substitute into 12 = (1/2)x(x+2)sin(30°), simplify using sin(30°) = 1/2, and solve the resulting quadratic equation x² + 2x - 48 = 0. While it requires multiple steps, each is routine and the question follows a standard template with no conceptual challenges.
Spec1.05c Area of triangle: using 1/2 ab sin(C)

2 \includegraphics[max width=\textwidth, alt={}, center]{ac5bf967-8b97-4bf3-991f-28c3ec7a25da-2_399_933_968_561} The diagram shows a triangle \(A B C\) in which angle \(C = 30 ^ { \circ } , B C = x \mathrm {~cm}\) and \(A C = ( x + 2 ) \mathrm { cm }\). Given that the area of triangle \(A B C\) is \(12 \mathrm {~cm} ^ { 2 }\), calculate the value of \(x\).

\(\frac{1}{2}x(x+2)\sin 30° = 12\) or simplified expression [B1]
Rearrange to get a quadratic equation including putting \(\sin 30° = \frac{1}{2}\) [M1]
Obtain \(x^2 + 2x - 48 = 0\) [A1]
Solve *their* quadratic equation [M1]
Obtain \(x = 6\) only [A1]
$\frac{1}{2}x(x+2)\sin 30° = 12$ or simplified expression [B1]

Rearrange to get a quadratic equation including putting $\sin 30° = \frac{1}{2}$ [M1]

Obtain $x^2 + 2x - 48 = 0$ [A1]

Solve *their* quadratic equation [M1]

Obtain $x = 6$ only [A1]
2\\
\includegraphics[max width=\textwidth, alt={}, center]{ac5bf967-8b97-4bf3-991f-28c3ec7a25da-2_399_933_968_561}

The diagram shows a triangle $A B C$ in which angle $C = 30 ^ { \circ } , B C = x \mathrm {~cm}$ and $A C = ( x + 2 ) \mathrm { cm }$. Given that the area of triangle $A B C$ is $12 \mathrm {~cm} ^ { 2 }$, calculate the value of $x$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/2 2016 Q2 [5]}}