Pre-U Pre-U 9795/1 2016 June — Question 10 10 marks

Exam BoardPre-U
ModulePre-U 9795/1 (Pre-U Further Mathematics Paper 1)
Year2016
SessionJune
Marks10
TopicPolar coordinates
TypeArea enclosed by polar curve
DifficultyChallenging +1.2 This is a Further Maths polar coordinates question requiring sketching and area calculation. While the absolute value adds a twist requiring identification of where the expression is negative, the actual integration is straightforward once set up. The topic itself (polar areas) is standard Further Maths content, and this is a typical two-part question with moderate algebraic manipulation but no deep conceptual insight required.
Spec4.09b Sketch polar curves: r = f(theta)4.09c Area enclosed: by polar curve

10
  1. Sketch the curve with polar equation \(r = \left| \frac { 1 } { 2 } + \sin \theta \right|\), for \(0 \leqslant \theta < 2 \pi\).
  2. Find in an exact form the total area enclosed by the curve.

Question 10 [6+4 marks]
(i)
\(\frac{1}{2}+\sin\theta = 0\) when \(\theta = \frac{7}{6}\pi,\ \frac{11}{6}\pi\) M1A1
Symmetry in \(y\)-axis B1
\(\left(\frac{1}{2}, 0\right)\) on initial line B1
Correct upper portion B1
Correct lower portion B1
[6]
(ii)
\(A = \left(\frac{1}{2}\right)\int_0^{2\pi}\left(\frac{1}{2}+\sin\theta\right)^2\,\mathrm{d}\theta\) M1 (Penalise incorrect multiples with final A0)
\(= \frac{1}{2}\int_0^{2\pi}\left(\frac{1}{4}+\sin\theta+\frac{1}{2}-\frac{1}{2}\cos 2\theta\right)\mathrm{d}\theta\) M1 (Double-angle formula)
\(= \frac{1}{2}\left[\frac{3}{4}\theta - \cos\theta - \frac{1}{4}\sin 2\theta\right]_0^{2\pi}\) A1 (correctly integrated 3 suitable terms)
\(= \frac{3}{4}\pi\) A1
[4]
**Question 10** [6+4 marks]

**(i)**
$\frac{1}{2}+\sin\theta = 0$ when $\theta = \frac{7}{6}\pi,\ \frac{11}{6}\pi$ M1A1

Symmetry in $y$-axis B1

$\left(\frac{1}{2}, 0\right)$ on initial line B1

Correct upper portion B1

Correct lower portion B1

**[6]**

**(ii)**
$A = \left(\frac{1}{2}\right)\int_0^{2\pi}\left(\frac{1}{2}+\sin\theta\right)^2\,\mathrm{d}\theta$ M1 (Penalise incorrect multiples with final A0)

$= \frac{1}{2}\int_0^{2\pi}\left(\frac{1}{4}+\sin\theta+\frac{1}{2}-\frac{1}{2}\cos 2\theta\right)\mathrm{d}\theta$ M1 (Double-angle formula)

$= \frac{1}{2}\left[\frac{3}{4}\theta - \cos\theta - \frac{1}{4}\sin 2\theta\right]_0^{2\pi}$ A1 (correctly integrated 3 suitable terms)

$= \frac{3}{4}\pi$ A1

**[4]**
10 (i) Sketch the curve with polar equation $r = \left| \frac { 1 } { 2 } + \sin \theta \right|$, for $0 \leqslant \theta < 2 \pi$.\\
(ii) Find in an exact form the total area enclosed by the curve.

\hfill \mbox{\textit{Pre-U Pre-U 9795/1 2016 Q10 [10]}}