Pre-U Pre-U 9794/1 2013 November — Question 11

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2013
SessionNovember
TopicComposite & Inverse Functions
TypeDetermine if inverse exists
DifficultyStandard +0.3 This is a straightforward composite and inverse functions question requiring standard techniques: finding range from domain, inverting a rational function, composing functions, and checking if a composite is one-to-one. Part (iii) requires recognizing that f(x) > 5 makes the absolute value redundant, which is a small insight but routine for this topic. Overall slightly easier than average A-level as it's methodical application of standard procedures.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence

11 The functions f and g are defined by \(\mathrm { f } ( x ) = \frac { 1 } { 2 + x } + 5 , x > - 2\) and \(\mathrm { g } ( x ) = | x | , x \in \mathbb { R }\).
  1. Given that the range of f is of the form \(\mathrm { f } ( x ) > a\), find \(a\).
  2. Find an expression for \(\mathrm { f } ^ { - 1 }\), stating its domain and range.
  3. Show that \(\mathrm { gf } ( x ) = \mathrm { f } ( x )\).
  4. Find an expression for \(\mathrm { fg } ( x )\). Determine whether fg has an inverse.

11 The functions f and g are defined by $\mathrm { f } ( x ) = \frac { 1 } { 2 + x } + 5 , x > - 2$ and $\mathrm { g } ( x ) = | x | , x \in \mathbb { R }$.\\
(i) Given that the range of f is of the form $\mathrm { f } ( x ) > a$, find $a$.\\
(ii) Find an expression for $\mathrm { f } ^ { - 1 }$, stating its domain and range.\\
(iii) Show that $\mathrm { gf } ( x ) = \mathrm { f } ( x )$.\\
(iv) Find an expression for $\mathrm { fg } ( x )$. Determine whether fg has an inverse.

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