| Exam Board | Pre-U |
|---|---|
| Module | Pre-U 9794/3 (Pre-U Mathematics Paper 3) |
| Year | 2012 |
| Session | June |
| Marks | 4 |
| Topic | Measures of Location and Spread |
| Type | Calculate statistics from raw data |
| Difficulty | Easy -1.8 This is a straightforward calculation requiring only direct application of mean and standard deviation formulas to a small dataset of 10 values. It involves basic arithmetic with no problem-solving, conceptual depth, or novel insight—purely routine statistical computation that's easier than typical A-level questions. |
| Spec | 2.02g Calculate mean and standard deviation |
Obtain 154.3 — B1
Attempt standard deviation formula — M1
Obtain $\sqrt{\left(\frac{239093}{10} - (154.3)^2\right)} = \sqrt{100.81}$ — A1
Obtain 10.0(4) — A1 [4]
**Total: [4]**
*With no working shown allow only correct answers. 154 used for sd (gives 13.9…) gets max M1A1A0. Allow unbiased estimator (10.58…) for full marks.*1 The heights in centimetres of 10 young women were measured and are given below.
$$\begin{array} { l l l l l l l l l l }
140 & 145 & 162 & 174 & 153 & 167 & 147 & 151 & 148 & 156
\end{array}$$
Calculate the mean height of these women and show that the standard deviation is approximately 10 cm .
\hfill \mbox{\textit{Pre-U Pre-U 9794/3 2012 Q1 [4]}}