OCR Further Mechanics 2021 June — Question 4 13 marks

Exam BoardOCR
ModuleFurther Mechanics (Further Mechanics)
Year2021
SessionJune
Marks13
TopicMoments
TypeResultant force on lamina
DifficultyStandard +0.8 This is a multi-part Further Maths mechanics question requiring center of mass calculation, equilibrium analysis on an inclined plane, elastic string theory (Hooke's law), and friction conditions. While each individual technique is standard, the combination of topics, the geometric setup with the inclined plane, and the need to resolve forces in multiple directions and take moments makes this significantly harder than typical A-level mechanics questions. The 'show that' format for parts (c) and (d) requires careful algebraic manipulation to reach specific numerical results.
Spec6.04b Find centre of mass: using symmetry6.04e Rigid body equilibrium: coplanar forces

4 Particles \(A , B\) and \(C\) of masses \(2 \mathrm {~kg} , 3 \mathrm {~kg}\) and 5 kg respectively are joined by light rigid rods to form a triangular frame. The frame is placed at rest on a horizontal plane with \(A\) at the point \(( 0,0 )\), \(B\) at the point ( \(0.6,0\) ) and \(C\) at the point ( \(0.4,0.2\) ), where distances in the coordinate system are measured in metres (see Fig. 1). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{709f3a7a-d857-4813-98ab-de6b41a3a8dc-03_311_661_338_258} \captionsetup{labelformat=empty} \caption{Fig. 1}
\end{figure} \(G\), which is the centre of mass of the frame, is at the point \(( \bar { x } , \bar { y } )\).
  1. - Show that \(\bar { x } = 0.38\).
    A rough plane, \(\Pi\), is inclined at an angle \(\theta\) to the horizontal where \(\sin \theta = \frac { 3 } { 5 }\). The frame is placed on \(\Pi\) with \(A B\) vertical and \(B\) in contact with \(\Pi . C\) is in the same vertical plane as \(A B\) and a line of greatest slope of \(\Pi . C\) is on the down-slope side of \(A B\). The frame is kept in equilibrium by a horizontal light elastic string whose natural length is \(l \mathrm {~m}\) and whose modulus of elasticity is \(g \mathrm {~N}\). The string is attached to \(A\) at one end and to a fixed point on \(\Pi\) at the other end (see Fig. 2). \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{709f3a7a-d857-4813-98ab-de6b41a3a8dc-03_605_828_1525_248} \captionsetup{labelformat=empty} \caption{Fig. 2}
    \end{figure} The coefficient of friction between \(B\) and \(\Pi\) is \(\mu\).
  2. Show that \(l = 0.3\).
  3. Show that \(\mu \geqslant \frac { 14 } { 27 }\).

4 Particles $A , B$ and $C$ of masses $2 \mathrm {~kg} , 3 \mathrm {~kg}$ and 5 kg respectively are joined by light rigid rods to form a triangular frame. The frame is placed at rest on a horizontal plane with $A$ at the point $( 0,0 )$, $B$ at the point ( $0.6,0$ ) and $C$ at the point ( $0.4,0.2$ ), where distances in the coordinate system are measured in metres (see Fig. 1).

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{709f3a7a-d857-4813-98ab-de6b41a3a8dc-03_311_661_338_258}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

$G$, which is the centre of mass of the frame, is at the point $( \bar { x } , \bar { y } )$.
\begin{enumerate}[label=(\alph*)]
\item - Show that $\bar { x } = 0.38$.

\begin{itemize}
  \item Find $\bar { y }$.
\item Explain why it would be impossible for the frame to be in equilibrium in a horizontal plane supported at only one point.
\end{itemize}

A rough plane, $\Pi$, is inclined at an angle $\theta$ to the horizontal where $\sin \theta = \frac { 3 } { 5 }$. The frame is placed on $\Pi$ with $A B$ vertical and $B$ in contact with $\Pi . C$ is in the same vertical plane as $A B$ and a line of greatest slope of $\Pi . C$ is on the down-slope side of $A B$.

The frame is kept in equilibrium by a horizontal light elastic string whose natural length is $l \mathrm {~m}$ and whose modulus of elasticity is $g \mathrm {~N}$. The string is attached to $A$ at one end and to a fixed point on $\Pi$ at the other end (see Fig. 2).

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{709f3a7a-d857-4813-98ab-de6b41a3a8dc-03_605_828_1525_248}
\captionsetup{labelformat=empty}
\caption{Fig. 2}
\end{center}
\end{figure}

The coefficient of friction between $B$ and $\Pi$ is $\mu$.
\item Show that $l = 0.3$.
\item Show that $\mu \geqslant \frac { 14 } { 27 }$.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Mechanics 2021 Q4 [13]}}