Find a vector which is perpendicular to both \(\left( \begin{array} { r } 1 3 - 2 \end{array} \right)\) and \(\left( \begin{array} { r } - 3 - 6 4 \end{array} \right)\).
The cartesian equation of a line is \(\frac { x } { 2 } = y - 3 = 2 z + 4\).
Express the equation of this line in vector form.