AQA Further Paper 2 2019 June — Question 11

Exam BoardAQA
ModuleFurther Paper 2 (Further Paper 2)
Year2019
SessionJune
TopicVectors: Cross Product & Distances

11 The line \(L _ { 1 }\) has equation $$\frac { x - 2 } { 3 } = \frac { y + 4 } { 8 } = \frac { 4 z - 5 } { 5 }$$ The line \(L _ { 2 }\) has equation $$\left( \mathbf { r } - \left[ \begin{array} { c } - 2
0
3 \end{array} \right] \right) \times \left[ \begin{array} { l } 2
1
3 \end{array} \right] = \mathbf { 0 }$$ Find the shortest distance between the two lines, giving your answer to three significant figures.