| Exam Board | AQA |
| Module | Further Paper 2 (Further Paper 2) |
| Year | 2019 |
| Session | June |
| Topic | Vectors: Cross Product & Distances |
11 The line \(L _ { 1 }\) has equation
$$\frac { x - 2 } { 3 } = \frac { y + 4 } { 8 } = \frac { 4 z - 5 } { 5 }$$
The line \(L _ { 2 }\) has equation
$$\left( \mathbf { r } - \left[ \begin{array} { c }
- 2
0
3
\end{array} \right] \right) \times \left[ \begin{array} { l }
2
1
3
\end{array} \right] = \mathbf { 0 }$$
Find the shortest distance between the two lines, giving your answer to three significant figures.