| Exam Board | AQA |
| Module | Further AS Paper 2 Mechanics (Further AS Paper 2 Mechanics) |
| Year | 2024 |
| Session | June |
| Topic | Dimensional Analysis |
6 Kepler's Third Law of planetary motion for the period of a circular orbit around the Earth is given by the formula,
$$t = 2 \pi \sqrt { \frac { r ^ { 3 } } { G m } }$$
where,
\(t\) is the time taken for one orbit
\(r\) is the radius of the circular orbit
\(m\) is the mass of the Earth
\(G\) is a gravitational constant.
Use dimensional analysis to determine the dimensions of \(G\)
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