Edexcel Paper 3 Specimen — Question 5 8 marks

Exam BoardEdexcel
ModulePaper 3 (Paper 3)
SessionSpecimen
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNormal Distribution
TypeDirect expected frequency calculation
DifficultyModerate -0.8 This is a straightforward normal distribution question requiring standard z-score lookups and basic probability calculations. Part (a) is routine (find P(X>160) then multiply by 12), part (b) is standard inverse normal application, and part (c) requires minimal statistical reasoning. All techniques are textbook exercises with no problem-solving insight needed.
Spec2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation

5. The lifetimes of batteries sold by company \(X\) are normally distributed, with mean 150 hours and standard deviation 25 hours. A box contains 12 batteries from company \(X\).
  1. Find the expected number of these batteries that have a lifetime of more than 160 hours. The lifetimes of batteries sold by company \(Y\) are normally distributed, with mean 160 hours and \(80 \%\) of these batteries have a lifetime of less than 180 hours.
  2. Find the standard deviation of the lifetimes of batteries from company \(Y\). Both companies sell their batteries for the same price.
  3. State which company you would recommend. Give reasons for your answer.

Question 5:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Using the model and horizontal motion: \(s = ut\)M1 Using the model and correct strategy
\(12 = T \times 45\cos10°\)A1 Correct equation in \(T\) only
\(T = 0.2707...\)A1 0.271 or better
Using the model and vertical motion: \(s = ut + \frac{1}{2}at^2\)M1 Using the model and correct strategy
\(s = 45T\sin10° + 4.9T^2\)A1 Correct equation
Correct strategy: sub for \(T\) and find \(s\)M1 Sub for \(T\) and solve for \(s\)
\(d = 3.5 - 2.4752 - 1\)M1 Correct method to find \(d\) using their \(s\)
\(= 2.5\) (cm) (2 SF)A1 2.5 is the only correct answer
(8 marks)
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Using the model and vertical motion: \(v = u + at\)M1 Using the model and correct strategy
\(v = 45\sin10° + 9.8T\)A1 Correct equation
Speed \(= ((45\cos10°)^2 + v^2)^{0.5}\)M1 Must have found a \(v\) and usual rules apply. Square root is needed
\(46\ (\text{m s}^{-1})\) (2 SF)A1 46 (2 SF) is only correct answer
(4 marks)
Part (c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Model does not take account of air resistanceB1 Other appropriate answer e.g. spin of the ball, wind effect
Model does not take account of the size of the tennis ballB1 Other appropriate answer e.g. spin of the ball, wind effect
(2 marks)
Total: 14 marks
# Question 5:

## Part (a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Using the model and horizontal motion: $s = ut$ | M1 | Using the model and correct strategy |
| $12 = T \times 45\cos10°$ | A1 | Correct equation in $T$ only |
| $T = 0.2707...$ | A1 | 0.271 or better |
| Using the model and vertical motion: $s = ut + \frac{1}{2}at^2$ | M1 | Using the model and correct strategy |
| $s = 45T\sin10° + 4.9T^2$ | A1 | Correct equation |
| Correct strategy: sub for $T$ and find $s$ | M1 | Sub for $T$ and solve for $s$ |
| $d = 3.5 - 2.4752 - 1$ | M1 | Correct method to find $d$ using their $s$ |
| $= 2.5$ (cm) (2 SF) | A1 | 2.5 is the only correct answer |

**(8 marks)**

## Part (b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Using the model and vertical motion: $v = u + at$ | M1 | Using the model and correct strategy |
| $v = 45\sin10° + 9.8T$ | A1 | Correct equation |
| Speed $= ((45\cos10°)^2 + v^2)^{0.5}$ | M1 | Must have found a $v$ and usual rules apply. Square root is needed |
| $46\ (\text{m s}^{-1})$ (2 SF) | A1 | 46 (2 SF) is only correct answer |

**(4 marks)**

## Part (c):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Model does not take account of air resistance | B1 | Other appropriate answer e.g. spin of the ball, wind effect |
| Model does not take account of the size of the tennis ball | B1 | Other appropriate answer e.g. spin of the ball, wind effect |

**(2 marks)**

**Total: 14 marks**
5. The lifetimes of batteries sold by company $X$ are normally distributed, with mean 150 hours and standard deviation 25 hours.

A box contains 12 batteries from company $X$.
\begin{enumerate}[label=(\alph*)]
\item Find the expected number of these batteries that have a lifetime of more than 160 hours.

The lifetimes of batteries sold by company $Y$ are normally distributed, with mean 160 hours and $80 \%$ of these batteries have a lifetime of less than 180 hours.
\item Find the standard deviation of the lifetimes of batteries from company $Y$.

Both companies sell their batteries for the same price.
\item State which company you would recommend. Give reasons for your answer.
\end{enumerate}

\hfill \mbox{\textit{Edexcel Paper 3  Q5 [8]}}