CAIE M1 2016 June — Question 1 4 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2016
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done against friction/resistance - inclined plane or slope
DifficultyModerate -0.3 This is a straightforward two-part mechanics question requiring standard formulas (ΔPE = mgh, work = force × distance) with minimal problem-solving. The constant speed condition simplifies the analysis, and all values are given directly. Slightly easier than average due to its routine nature, though the two-step calculation in part (ii) prevents it from being trivial.
Spec6.02a Work done: concept and definition6.02d Mechanical energy: KE and PE concepts

1 A particle of mass 8 kg is pulled at a constant speed a distance of 20 m up a rough plane inclined at an angle of \(30 ^ { \circ }\) to the horizontal by a force acting along a line of greatest slope.
  1. Find the change in gravitational potential energy of the particle.
  2. The total work done against gravity and friction is 1146 J . Find the frictional force acting on the particle.

Question 1:
Part (i):
AnswerMarks Guidance
AnswerMark Guidance
\([\text{PE gain} = 8g \times 20\sin30°]\)M1 For using PE gain \(= mgh\)
Change in PE is 800 JA1 [2 marks]
Part (ii):
AnswerMarks Guidance
AnswerMark Guidance
\([8g \times 20\sin30° + 20F = 1146]\)M1 For using PE gain + WD against friction \(= 1146\)
Frictional force is 17.3 NA1 [2 marks]
## Question 1:

### Part (i):
| Answer | Mark | Guidance |
|--------|------|----------|
| $[\text{PE gain} = 8g \times 20\sin30°]$ | M1 | For using PE gain $= mgh$ |
| Change in PE is 800 J | A1 | **[2 marks]** |

### Part (ii):
| Answer | Mark | Guidance |
|--------|------|----------|
| $[8g \times 20\sin30° + 20F = 1146]$ | M1 | For using PE gain + WD against friction $= 1146$ |
| Frictional force is 17.3 N | A1 | **[2 marks]** |

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1 A particle of mass 8 kg is pulled at a constant speed a distance of 20 m up a rough plane inclined at an angle of $30 ^ { \circ }$ to the horizontal by a force acting along a line of greatest slope.\\
(i) Find the change in gravitational potential energy of the particle.\\
(ii) The total work done against gravity and friction is 1146 J . Find the frictional force acting on the particle.

\hfill \mbox{\textit{CAIE M1 2016 Q1 [4]}}