AQA Paper 3 2023 June — Question 7

Exam BoardAQA
ModulePaper 3 (Paper 3)
Year2023
SessionJune
TopicIntegration by Substitution

7 A new design for a company logo is to be made from two sectors of a circle, ORP and OQS, and a rhombus OSTR, as shown in the diagram below.
\includegraphics[max width=\textwidth, alt={}, center]{6fba7e53-de46-460b-9bef-f1a6962f2e7d-08_509_584_408_817} The points \(P , O\) and \(Q\) lie on a straight line and the angle \(R O S\) is \(\theta\) radians.
A large copy of the logo, with \(P Q = 5\) metres, is to be put on a wall.
7
  1. Show that the area of the logo, \(A\) square metres, is given by $$A = \frac { 25 } { 8 } ( \pi - \theta + 2 \sin \theta )$$ \section*{-
    7
    1. Show that the maximum value of \(A\) occurs when \(\theta = \frac { \pi } { 3 }\)
      Fully justify your answer.} 7
  2. (ii) Find the exact maximum value of \(A\)
    7
  3. Without further calculation, state how your answers to parts (b)(i) and (b)(ii) would change if \(P Q\) were increased to 10 metres.
    \includegraphics[max width=\textwidth, alt={}, center]{6fba7e53-de46-460b-9bef-f1a6962f2e7d-11_2488_1716_219_153} Use the substitution \(u = x ^ { 5 } + 2\) to show that $$\int _ { 0 } ^ { 1 } \frac { x ^ { 9 } } { \left( x ^ { 5 } + 2 \right) ^ { 3 } } \mathrm {~d} x = \frac { 1 } { 180 }$$