A student states that 3 is the smallest value of \(k\) in the interval \(3 < k < 4\)
Explain the error in the student's statement.
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The student's teacher says there is no smallest value of \(k\) in the interval \(3 < k < 4\) The teacher gives the following correct proof:
Step 1: Assume there is a smallest number in the interval \(3 < k < 4\) and let this smallest number be \(x\)
Step 2: let \(y = \frac { 3 + x } { 2 }\)
Step 3: \(3 < y < x\) which is a contradiction.
Step 4: Therefore, there is no smallest number in interval \(3 < k < 4\)
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Explain the contradiction stated in Step 3
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(ii) Prove that there is no largest value of \(k\) in the interval \(3 < k < 4\)
\section*{END OF SECTION A TURN OVER FOR SECTION B}