| Exam Board | AQA |
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| Module | Paper 2 (Paper 2) |
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| Year | 2020 |
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| Session | June |
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| Marks | 6 |
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| Topic | Integration by Substitution |
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5 Use integration by substitution to show that
$$\int _ { - \frac { 1 } { 4 } } ^ { 6 } x \sqrt { 4 x + 1 } \mathrm {~d} x = \frac { 875 } { 12 }$$
Fully justify your answer.
[0pt]
[6 marks]