CAIE M1 2015 June — Question 2 5 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2015
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeFind acceleration on incline given power
DifficultyModerate -0.3 This is a straightforward application of the power-force-velocity relationship (P = Fv) combined with Newton's second law. Part (i) requires simple substitution into standard formulas, while part (ii) adds an incline component but remains routine. The zero resistance simplifies calculations, and both parts follow standard M1 procedures without requiring problem-solving insight.
Spec6.02l Power and velocity: P = Fv

2 The total mass of a cyclist and his cycle is 80 kg . The resistance to motion is zero.
  1. The cyclist moves along a horizontal straight road working at a constant rate of \(P \mathrm {~W}\). Find the value of \(P\) given that the cyclist's speed is \(5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) when his acceleration is \(1.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }\).
  2. The cyclist moves up a straight hill inclined at an angle \(\alpha\), where \(\sin \alpha = 0.035\). Find the acceleration of the cyclist at an instant when he is working at a rate of 450 W and has speed \(3.6 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).

Question 2:
Part (i)
AnswerMarks Guidance
Working/AnswerMark Guidance
\(\frac{P}{5} = 80 \times 1.2\)M1 For using \(DF = \frac{P}{v}\) and Newton's 2nd law
\(P = 480\)A1 [2]
Part (ii)
AnswerMarks Guidance
Working/AnswerMark Guidance
\(\frac{450}{3.6} - 80g \times 0.035 = 80a\)M1, A1 For using \(\frac{P}{v} - W\sin\alpha = ma\)
Acceleration is \(1.21\) ms\(^{-2}\)A1 [3] Allow \(a = \frac{97}{80}\)
## Question 2:

### Part (i)

| Working/Answer | Mark | Guidance |
|---|---|---|
| $\frac{P}{5} = 80 \times 1.2$ | M1 | For using $DF = \frac{P}{v}$ and Newton's 2nd law |
| $P = 480$ | A1 | **[2]** |

### Part (ii)

| Working/Answer | Mark | Guidance |
|---|---|---|
| $\frac{450}{3.6} - 80g \times 0.035 = 80a$ | M1, A1 | For using $\frac{P}{v} - W\sin\alpha = ma$ |
| Acceleration is $1.21$ ms$^{-2}$ | A1 | **[3]** Allow $a = \frac{97}{80}$ |

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2 The total mass of a cyclist and his cycle is 80 kg . The resistance to motion is zero.\\
(i) The cyclist moves along a horizontal straight road working at a constant rate of $P \mathrm {~W}$. Find the value of $P$ given that the cyclist's speed is $5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ when his acceleration is $1.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }$.\\
(ii) The cyclist moves up a straight hill inclined at an angle $\alpha$, where $\sin \alpha = 0.035$. Find the acceleration of the cyclist at an instant when he is working at a rate of 450 W and has speed $3.6 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.

\hfill \mbox{\textit{CAIE M1 2015 Q2 [5]}}