CAIE M1 2013 June — Question 1 4 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2013
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFriction
TypeBlock on horizontal plane motion
DifficultyModerate -0.3 Part (i) requires basic conceptual understanding of friction (vertical force reduces normal reaction, making it easier to move the block). Part (ii) is a standard application of F=ma and friction laws with straightforward arithmetic. Both parts are routine M1 exercises requiring no problem-solving insight, though slightly easier than average due to the conceptual nature of part (i) and simple single-step calculation in part (ii).
Spec3.03u Static equilibrium: on rough surfaces3.03v Motion on rough surface: including inclined planes

1 A block is at rest on a rough horizontal plane. The coefficient of friction between the block and the plane is 1.25 .
  1. State, giving a reason for your answer, whether the minimum vertical force required to move the block is greater or less than the minimum horizontal force required to move the block. A horizontal force of continuously increasing magnitude \(P \mathrm {~N}\) and fixed direction is applied to the block.
  2. Given that the weight of the block is 60 N , find the value of \(P\) when the acceleration of the block is \(4 \mathrm {~m} \mathrm {~s} ^ { - 2 }\).

Question 1:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
Less thanB1
\(F = 1.25W\) so \(W < F\)B1 [2]
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\([P - 60 \times 1.25 = 6 \times 4]\)M1 For applying Newton's second law
\(P = 99\)A1 [2]
## Question 1:

### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| Less than | B1 | |
| $F = 1.25W$ so $W < F$ | B1 | [2] |

### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $[P - 60 \times 1.25 = 6 \times 4]$ | M1 | For applying Newton's second law |
| $P = 99$ | A1 | [2] |

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1 A block is at rest on a rough horizontal plane. The coefficient of friction between the block and the plane is 1.25 .\\
(i) State, giving a reason for your answer, whether the minimum vertical force required to move the block is greater or less than the minimum horizontal force required to move the block.

A horizontal force of continuously increasing magnitude $P \mathrm {~N}$ and fixed direction is applied to the block.\\
(ii) Given that the weight of the block is 60 N , find the value of $P$ when the acceleration of the block is $4 \mathrm {~m} \mathrm {~s} ^ { - 2 }$.

\hfill \mbox{\textit{CAIE M1 2013 Q1 [4]}}