| Exam Board | OCR |
|---|---|
| Module | H240/01 (Pure Mathematics) |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Topic | Product & Quotient Rules |
| Type | Implicit or inverse differentiation |
| Difficulty | Standard +0.3 This is a straightforward implicit differentiation question requiring the product rule. Part (a) is direct application of d/dy[(y+5)ln(2y-7)], and part (b) requires finding y when x=0 then substituting. Slightly easier than average as it avoids the complexity of dy/dx = 1/(dx/dy) by asking directly for dx/dy, and the algebra is clean. |
| Spec | 1.07l Derivative of ln(x): and related functions1.07s Parametric and implicit differentiation |
10 A curve has equation $x = ( y + 5 ) \ln ( 2 y - 7 )$.
\begin{enumerate}[label=(\alph*)]
\item Find $\frac { \mathrm { d } x } { \mathrm {~d} y }$ in terms of y .
\item Find the gradient of the curve where it crosses the y -axis.
\end{enumerate}
\hfill \mbox{\textit{OCR H240/01 Q10 [8]}}