CAIE M1 2012 June — Question 1 3 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2012
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done by constant force - find unknown force, angle, or distance
DifficultyEasy -1.2 This is a straightforward one-step application of the work formula W = Fs cos θ, requiring only substitution of given values (75 = F × 5 × cos 60°) and basic algebraic rearrangement to find F = 30 N. It's simpler than average as it involves direct recall of a standard formula with no problem-solving or multi-step reasoning required.
Spec6.02b Calculate work: constant force, resolved component

1 A block is pulled in a straight line along horizontal ground by a force of constant magnitude acting at an angle of \(60 ^ { \circ }\) above the horizontal. The work done by the force in moving the block a distance of 5 m is 75 J . Find the magnitude of the force.

Question 1:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(F \times 5\cos60° = 75\)M1 For using \(WD = Fd\cos\alpha\)
\(F \times 5\cos60° = 75\)A1
Magnitude of the force is 30 NA1 [3]
# Question 1:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $F \times 5\cos60° = 75$ | M1 | For using $WD = Fd\cos\alpha$ |
| $F \times 5\cos60° = 75$ | A1 | |
| Magnitude of the force is 30 N | A1 | [3] |

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1 A block is pulled in a straight line along horizontal ground by a force of constant magnitude acting at an angle of $60 ^ { \circ }$ above the horizontal. The work done by the force in moving the block a distance of 5 m is 75 J . Find the magnitude of the force.

\hfill \mbox{\textit{CAIE M1 2012 Q1 [3]}}