Moderate -0.3 This is a straightforward application of the power-force-velocity relationship (P = Fv) combined with Newton's second law. Students must find the driving force using F = ma + resistance, then calculate P = Fv. It requires two standard formulas with clear given values and minimal problem-solving insight, making it slightly easier than average.
1 A car of mass 880 kg travels along a straight horizontal road with its engine working at a constant rate of \(P \mathrm {~W}\). The resistance to motion is 700 N . At an instant when the car's speed is \(16 \mathrm {~ms} ^ { - 1 }\) its acceleration is \(0.625 \mathrm {~m} \mathrm {~s} ^ { - 2 }\). Find the value of \(P\).
1 A car of mass 880 kg travels along a straight horizontal road with its engine working at a constant rate of $P \mathrm {~W}$. The resistance to motion is 700 N . At an instant when the car's speed is $16 \mathrm {~ms} ^ { - 1 }$ its acceleration is $0.625 \mathrm {~m} \mathrm {~s} ^ { - 2 }$. Find the value of $P$.
\hfill \mbox{\textit{CAIE M1 2012 Q1 [4]}}