CAIE M1 2011 June — Question 1 3 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2011
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done by constant force - find unknown force, angle, or distance
DifficultyModerate -0.8 This is a straightforward application of the work formula W = Fs cos(α). Students substitute given values (8200 = 180 × 50 × cos α), rearrange to find cos α, then use inverse cosine. It requires only direct recall of one formula and basic algebraic manipulation with no problem-solving insight needed.
Spec6.02b Calculate work: constant force, resolved component

1 A block is pulled for a distance of 50 m along a horizontal floor, by a rope that is inclined at an angle of \(\alpha ^ { \circ }\) to the floor. The tension in the rope is 180 N and the work done by the tension is 8200 J . Find the value of \(\alpha\).

Question 1:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(8200 = 180 \times 50 \cos\alpha\)M1 For using \(WD = Fd\cos\alpha\)
A1
\(\alpha = 24.3\)A1 [3]
## Question 1:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $8200 = 180 \times 50 \cos\alpha$ | M1 | For using $WD = Fd\cos\alpha$ |
| | A1 | |
| $\alpha = 24.3$ | A1 **[3]** | |

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1 A block is pulled for a distance of 50 m along a horizontal floor, by a rope that is inclined at an angle of $\alpha ^ { \circ }$ to the floor. The tension in the rope is 180 N and the work done by the tension is 8200 J . Find the value of $\alpha$.

\hfill \mbox{\textit{CAIE M1 2011 Q1 [3]}}