| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2008 |
| Session | June |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Power and driving force |
| Type | Power from work done over time (P = W/t) |
| Difficulty | Moderate -0.8 This is a straightforward application of standard work-energy formulas (Work = Force × distance × cos θ, Power = Work/time) with clearly stated values and minimal problem-solving required. The question explicitly guides students through the calculation in two parts, making it easier than average for A-level mechanics. |
| Spec | 6.02a Work done: concept and definition6.02l Power and velocity: P = Fv |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Distance is \(2.5 \times 12\) m or \(\text{power} = 851\cos20° \times 2.5\) | B1 | |
| \([WD = 851 \times 30\cos20°]\) | M1 | For using \(WD = T d\cos\alpha\) (or Pt) |
| Work done is 24 kJ | A1 [3] | AG |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Power is 2 kW | B1 [1] |
## Question 2:
### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| Distance is $2.5 \times 12$ m **or** $\text{power} = 851\cos20° \times 2.5$ | B1 | |
| $[WD = 851 \times 30\cos20°]$ | M1 | For using $WD = T d\cos\alpha$ (or Pt) |
| Work done is 24 kJ | A1 [3] | AG |
### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| Power is 2 kW | B1 [1] | |
---2 A block is being pulled along a horizontal floor by a rope inclined at $20 ^ { \circ }$ to the horizontal. The tension in the rope is 851 N and the block moves at a constant speed of $2.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.\\
(i) Show that the work done on the block in 12 s is approximately 24 kJ .\\
(ii) Hence find the power being applied to the block, giving your answer to the nearest kW .
\hfill \mbox{\textit{CAIE M1 2008 Q2 [4]}}