CAIE M1 2007 June — Question 3 6 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2007
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeFind steady/maximum speed given power
DifficultyModerate -0.5 This is a straightforward application of the power-force-velocity relationship (P=Fv) at maximum speed where acceleration is zero, followed by Newton's second law. Both parts require direct substitution into standard formulas with minimal problem-solving insight needed.
Spec3.03c Newton's second law: F=ma one dimension6.02l Power and velocity: P = Fv

3 A car travels along a horizontal straight road with increasing speed until it reaches its maximum speed of \(30 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The resistance to motion is constant and equal to \(R \mathrm {~N}\), and the power provided by the car's engine is 18 kW .
  1. Find the value of \(R\).
  2. Given that the car has mass 1200 kg , find its acceleration at the instant when its speed is \(20 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).

Question 3:
Part (i):
AnswerMarks Guidance
Working/AnswerMark Guidance
\([DF = 18000/30]\)M1 For using \(DF = P/v\) — may be scored in (ii)
\([R = DF]\)M1 For using \(a = 0\) (may be implied)
\(R = 600\ \text{N}\)A1
Part (ii):
AnswerMarks Guidance
Working/AnswerMark Guidance
M1For using Newton's second law (3 terms)
\(18000/20 - 600 = 1200a\)A1ft ft wrong \(R\)
Acceleration is \(0.25\ \text{ms}^{-2}\)A1
## Question 3:

### Part (i):
| Working/Answer | Mark | Guidance |
|---|---|---|
| $[DF = 18000/30]$ | M1 | For using $DF = P/v$ — may be scored in (ii) |
| $[R = DF]$ | M1 | For using $a = 0$ (may be implied) |
| $R = 600\ \text{N}$ | A1 | |

### Part (ii):
| Working/Answer | Mark | Guidance |
|---|---|---|
| | M1 | For using Newton's second law (3 terms) |
| $18000/20 - 600 = 1200a$ | A1ft | ft wrong $R$ |
| Acceleration is $0.25\ \text{ms}^{-2}$ | A1 | |

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3 A car travels along a horizontal straight road with increasing speed until it reaches its maximum speed of $30 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. The resistance to motion is constant and equal to $R \mathrm {~N}$, and the power provided by the car's engine is 18 kW .\\
(i) Find the value of $R$.\\
(ii) Given that the car has mass 1200 kg , find its acceleration at the instant when its speed is $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.

\hfill \mbox{\textit{CAIE M1 2007 Q3 [6]}}