8. Liquid is pouring into a container at a constant rate of \(20 \mathrm {~cm} ^ { 3 } \mathrm {~s} ^ { - 1 }\) and is leaking out at a rate proportional to the volume of the liquid already in the container.
- Explain why, at time \(t\) seconds, the volume, \(V \mathrm {~cm} ^ { 3 }\), of liquid in the container satisfies the differential equation
$$\frac { \mathrm { d } V } { \mathrm {~d} t } = 20 - k V$$
where \(k\) is a positive constant.
The container is initially empty.
- By solving the differential equation, show that
$$V = A + B \mathrm { e } ^ { - k t }$$
giving the values of \(A\) and \(B\) in terms of \(k\).
Given also that \(\frac { \mathrm { d } V } { \mathrm {~d} t } = 10\) when \(t = 5\),
- find the volume of liquid in the container at 10 s after the start.
Materials required for examination
Mathematical Formulae (Green)
Items included with question papers
Nil
Paper Reference(s)
6666
\section*{Advanced Level}
\section*{Monday 23 January 2006 - Afternoon}
Candidates may use any calculator EXCEPT those with the facility for symbolic algebra, differentiation and/or integration. Thus candidates may NOT use calculators such as the Texas Instruments TI 89, TI 92, Casio CFX 9970G, Hewlett Packard HP 48G.