9. The gradient of the curve \(C\) is given by
$$\frac { \mathrm { d } y } { \mathrm {~d} x } = ( 3 x - 1 ) ^ { 2 }$$
The point \(P ( 1,4 )\) lies on \(C\).
- Find an equation of the normal to \(C\) at \(P\).
- Find an equation for the curve \(C\) in the form \(y = \mathrm { f } ( x )\).
- Using \(\frac { \mathrm { d } y } { \mathrm {~d} x } = ( 3 x - 1 ) ^ { 2 }\), show that there is no point on \(C\) at which the tangent is parallel to the line \(y = 1 - 2 x\).