OCR H240/01 2018 December — Question 3 6 marks

Exam BoardOCR
ModuleH240/01 (Pure Mathematics)
Year2018
SessionDecember
Marks6
TopicReciprocal Trig & Identities
TypeGiven one function find others
DifficultyModerate -0.3 Part (a) is a straightforward application of the Pythagorean identity sin²α + cos²α = 1, requiring simple substitution and square root extraction. Part (b) requires recognizing that tan²β = sec²β - 1 to convert to a quadratic in sec β, then solving—this is slightly more involved but still a standard textbook exercise testing basic trig identities. Overall slightly easier than average due to routine application of well-known identities.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^2

3 In this question you must show detailed reasoning.
  1. Given that \(\sin \alpha = \frac { 2 } { 3 }\), find the exact values of \(\cos \alpha\).
  2. Given that \(2 \tan ^ { 2 } \beta - 7 \sec \beta + 5 = 0\), find the exact value of \(\sec \beta\).

3 In this question you must show detailed reasoning.
\begin{enumerate}[label=(\alph*)]
\item Given that $\sin \alpha = \frac { 2 } { 3 }$, find the exact values of $\cos \alpha$.
\item Given that $2 \tan ^ { 2 } \beta - 7 \sec \beta + 5 = 0$, find the exact value of $\sec \beta$.
\end{enumerate}

\hfill \mbox{\textit{OCR H240/01 2018 Q3 [6]}}