OCR Further Statistics 2018 December — Question 2 7 marks

Exam BoardOCR
ModuleFurther Statistics (Further Statistics)
Year2018
SessionDecember
Marks7
TopicDiscrete Probability Distributions
TypeTwo unknowns from sum and expectation
DifficultyModerate -0.3 This is a straightforward probability distribution question requiring standard techniques: using sum of probabilities equals 1 and expectation formula to find two unknowns (part a), then calculating variance (part b) and linear transformation of expectation (part c). All steps are routine applications of formulas with no conceptual challenges or novel problem-solving required, making it slightly easier than average.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables

2 In a fairground game a competitor scores \(0,1,2\) or 3 with probabilities given in the following table, where \(a\) and \(b\) are constants.
Score0123
Probability\(a\)\(b\)\(b\)\(b\)
The competitor's expected score is 0.9 .
  1. Show that \(b = 0.15\).
  2. Find the variance of the score.
  3. The competitor has to pay \(\pounds 2.50\) to take part, and wins a prize of \(\pounds 2 X\), where \(X\) is the score achieved. Find the expectation of the competitor's loss.

(a)
\(0a + b + 2b + 3b = 0.9\)
\(b = 0.15\) AG
AnswerMarks
M1, A1www [NB: a not needed]
(b)
\(0a + 1b + 4b + 9b\)
\(-0.9^2\)
\(= 1.29\)
AnswerMarks
M1, M1, A1(no additional guidance)
(c)
\(E(2X - 2.5) = -0.7\)
Expected loss is 70p
AnswerMarks
M1, A1Or £0.70 but not £0.7; Accept -70p oe
## (a)
$0a + b + 2b + 3b = 0.9$

$b = 0.15$ AG

| M1, A1 | www [NB: a not needed] |

## (b)
$0a + 1b + 4b + 9b$

$-0.9^2$

$= 1.29$

| M1, M1, A1 | (no additional guidance) |

## (c)
$E(2X - 2.5) = -0.7$

Expected loss is 70p

| M1, A1 | Or £0.70 but not £0.7; Accept -70p oe |

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2 In a fairground game a competitor scores $0,1,2$ or 3 with probabilities given in the following table, where $a$ and $b$ are constants.

\begin{center}
\begin{tabular}{ | l | c | c | c | c | }
\hline
Score & 0 & 1 & 2 & 3 \\
\hline
Probability & $a$ & $b$ & $b$ & $b$ \\
\hline
\end{tabular}
\end{center}

The competitor's expected score is 0.9 .
\begin{enumerate}[label=(\alph*)]
\item Show that $b = 0.15$.
\item Find the variance of the score.
\item The competitor has to pay $\pounds 2.50$ to take part, and wins a prize of $\pounds 2 X$, where $X$ is the score achieved. Find the expectation of the competitor's loss.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Statistics 2018 Q2 [7]}}