Moderate -0.8 This is a straightforward dimensional analysis problem requiring rearrangement of a given formula to isolate G, then substituting standard dimensions for force, mass, and distance. It's routine algebraic manipulation with no conceptual difficulty beyond knowing that [F] = MLT^-2, making it easier than average.
2 The universal law of gravitation states that \(F = \frac { G m _ { 1 } m _ { 2 } } { r ^ { 2 } }\) where \(F\) is the magnitude of the force between two objects of masses \(m _ { 1 }\) and \(m _ { 2 }\) which are a distance \(r\) apart and \(G\) is a constant.
Find the dimensions of \(G\).
2 The universal law of gravitation states that $F = \frac { G m _ { 1 } m _ { 2 } } { r ^ { 2 } }$ where $F$ is the magnitude of the force between two objects of masses $m _ { 1 }$ and $m _ { 2 }$ which are a distance $r$ apart and $G$ is a constant.
Find the dimensions of $G$.
\hfill \mbox{\textit{OCR FM1 AS 2017 Q2 [4]}}