CAIE M1 2020 November — Question 2 4 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2020
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeWork done against friction/resistance - inclined plane or slope
DifficultyModerate -0.8 This is a straightforward multi-part mechanics question requiring standard formulas: work = force × distance for part (a), mgh for part (b), and combining results for part (c). All steps are routine applications of basic mechanics principles with no problem-solving insight required, making it easier than average but not trivial due to the multi-part structure.
Spec6.02b Calculate work: constant force, resolved component6.02d Mechanical energy: KE and PE concepts

2 A box of mass 5 kg is pulled at a constant speed a distance of 15 m up a rough plane inclined at an angle of \(20 ^ { \circ }\) to the horizontal. The box moves along a line of greatest slope against a frictional force of 40 N . The force pulling the box is parallel to the line of greatest slope.
  1. Find the work done against friction.
  2. Find the change in gravitational potential energy of the box.
  3. Find the work done by the pulling force.

Question 2:
Part (a)
AnswerMarks Guidance
AnswerMarks Guidance
\(WD = 40 \times 15 = 600\ \text{J}\)B1
[1]
Part (b)
AnswerMarks Guidance
AnswerMarks Guidance
\([PE = 5 \times 10 \times 15 \sin 20]\)M1 Attempt PE gain
\(257\ \text{J}\ (256.5151\ldots\ \text{J})\)A1
[2]
Part (c)
AnswerMarks Guidance
AnswerMarks Guidance
\(WD = 40 \times 15 + 5 \times 10 \times 15 \sin 20 = 857\ \text{J}\)B1 FT FT \(600 +\ \)'PE'\((> 0)\) from 2(b)
[1]
## Question 2:

**Part (a)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $WD = 40 \times 15 = 600\ \text{J}$ | **B1** | |
| | **[1]** | |

**Part (b)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $[PE = 5 \times 10 \times 15 \sin 20]$ | **M1** | Attempt PE gain |
| $257\ \text{J}\ (256.5151\ldots\ \text{J})$ | **A1** | |
| | **[2]** | |

**Part (c)**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $WD = 40 \times 15 + 5 \times 10 \times 15 \sin 20 = 857\ \text{J}$ | **B1 FT** | FT $600 +\ $'PE'$(> 0)$ from **2(b)** |
| | **[1]** | |
2 A box of mass 5 kg is pulled at a constant speed a distance of 15 m up a rough plane inclined at an angle of $20 ^ { \circ }$ to the horizontal. The box moves along a line of greatest slope against a frictional force of 40 N . The force pulling the box is parallel to the line of greatest slope.
\begin{enumerate}[label=(\alph*)]
\item Find the work done against friction.
\item Find the change in gravitational potential energy of the box.
\item Find the work done by the pulling force.
\end{enumerate}

\hfill \mbox{\textit{CAIE M1 2020 Q2 [4]}}