SPS SPS SM Pure 2023 February — Question 14 10 marks

Exam BoardSPS
ModuleSPS SM Pure (SPS SM Pure)
Year2023
SessionFebruary
Marks10
TopicGeometric Sequences and Series
TypeFind first term from conditions
DifficultyStandard +0.3 This is a straightforward geometric series problem requiring standard formulas (S∞ = a/(1-r), ar = 18) to find a and r, then algebraic manipulation of the nth term formula and basic logarithm laws. While multi-part with 7 marks total, each step follows routine procedures without requiring problem-solving insight or novel approaches, making it slightly easier than average.
Spec1.04i Geometric sequences: nth term and finite series sum1.04j Sum to infinity: convergent geometric series |r|<11.06f Laws of logarithms: addition, subtraction, power rules

14. The sum to infinity of a geometric series is 96
The first term of the series is less than 30
The second term of the series is 18
  1. Find the first term and common ratio of the series.
    [0pt] [4 marks]
  2. (i) Show that the \(n\)th term of the series, \(u _ { n }\), can be written as $$u _ { n } = \frac { 3 ^ { n } } { 2 ^ { 2 n - 5 } }$$ [3 marks]
    (b) (ii) Hence show that $$\log _ { 3 } u _ { n } = n \left( 1 - 2 \log _ { 3 } 2 \right) + 5 \log _ { 3 } 2$$

14.

The sum to infinity of a geometric series is 96\\
The first term of the series is less than 30\\
The second term of the series is 18
\begin{enumerate}[label=(\alph*)]
\item Find the first term and common ratio of the series.\\[0pt]
[4 marks]
\item (i) Show that the $n$th term of the series, $u _ { n }$, can be written as

$$u _ { n } = \frac { 3 ^ { n } } { 2 ^ { 2 n - 5 } }$$

[3 marks]\\
(b) (ii) Hence show that

$$\log _ { 3 } u _ { n } = n \left( 1 - 2 \log _ { 3 } 2 \right) + 5 \log _ { 3 } 2$$
\end{enumerate}

\hfill \mbox{\textit{SPS SPS SM Pure 2023 Q14 [10]}}