SPS SPS FM Pure 2023 November — Question 3 12 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2023
SessionNovember
Marks12
TopicChain Rule
TypeEquation of normal line
DifficultyModerate -0.8 This is a straightforward differentiation and tangent/normal question requiring standard techniques: differentiating powers of x (including fractional and negative powers), verifying a point lies on a curve by substitution, finding the gradient at a point, and using the perpendicular gradient property for normals. All steps are routine A-level procedures with no problem-solving insight required, making it easier than average but not trivial due to the algebraic manipulation involved.
Spec1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations

3. The curve \(C\) has equation $$y = \frac { 1 } { 2 } x ^ { 3 } - 9 x ^ { \frac { 3 } { 2 } } + \frac { 8 } { x } + 30 , \quad x > 0$$
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\).
  2. Show that the point \(P ( 4 , - 8 )\) lies on \(C\).
  3. Find an equation of the normal to \(C\) at the point \(P\), giving your answer in the form \(a x + b y + c = 0\), where \(a , b\) and \(c\) are integers.
    [0pt]

3. The curve $C$ has equation

$$y = \frac { 1 } { 2 } x ^ { 3 } - 9 x ^ { \frac { 3 } { 2 } } + \frac { 8 } { x } + 30 , \quad x > 0$$
\begin{enumerate}[label=(\alph*)]
\item Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$.
\item Show that the point $P ( 4 , - 8 )$ lies on $C$.
\item Find an equation of the normal to $C$ at the point $P$, giving your answer in the form $a x + b y + c = 0$, where $a , b$ and $c$ are integers.\\[0pt]

\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2023 Q3 [12]}}