SPS SPS SM Statistics 2021 September — Question 1 6 marks

Exam BoardSPS
ModuleSPS SM Statistics (SPS SM Statistics)
Year2021
SessionSeptember
Marks6
TopicMeasures of Location and Spread
TypeCalculate statistics from grouped frequency table
DifficultyEasy -1.2 This is a routine statistics question testing standard procedures: finding median from cumulative frequency (straightforward interpolation in the 20-29 class), calculating mean and standard deviation using given summations with standard formulas, and explaining right-skew. All techniques are direct textbook applications with no problem-solving or insight required.
Spec2.02f Measures of average and spread2.02g Calculate mean and standard deviation

  1. A random sample of distances travelled to work for 120 commuters from a train station in Devon is recorded. The distances travelled, to the nearest mile, are summarised below.
Distance (to the nearest mile)Number of commuters
0-910
10-1919
20-2943
30-3925
40-498
50-596
60-695
70-793
80-891
For this distribution:
a estimate the median. The mid-point of each class was represented by \(x\) and its corresponding frequency by \(f\). The mid-point of the lowest class was taken to be 4.75 giving: $$\Sigma f x = 3552.5 \text { and } \Sigma f x ^ { 2 } = 138043.125$$ b Estimate the mean and the standard deviation of this distribution.
c Explain why the median is less than the mean for these data.
[0pt]

\begin{enumerate}
  \item A random sample of distances travelled to work for 120 commuters from a train station in Devon is recorded. The distances travelled, to the nearest mile, are summarised below.
\end{enumerate}

\begin{center}
\begin{tabular}{|l|l|}
\hline
Distance (to the nearest mile) & Number of commuters \\
\hline
0-9 & 10 \\
\hline
10-19 & 19 \\
\hline
20-29 & 43 \\
\hline
30-39 & 25 \\
\hline
40-49 & 8 \\
\hline
50-59 & 6 \\
\hline
60-69 & 5 \\
\hline
70-79 & 3 \\
\hline
80-89 & 1 \\
\hline
\end{tabular}
\end{center}

For this distribution:\\
a estimate the median.

The mid-point of each class was represented by $x$ and its corresponding frequency by $f$. The mid-point of the lowest class was taken to be 4.75 giving:

$$\Sigma f x = 3552.5 \text { and } \Sigma f x ^ { 2 } = 138043.125$$

b Estimate the mean and the standard deviation of this distribution.\\
c Explain why the median is less than the mean for these data.\\[0pt]
\\

\hfill \mbox{\textit{SPS SPS SM Statistics 2021 Q1 [6]}}